Every rational number has a base-2 representation, but only the ones with denominators that are powers of 2 will require a finite number of bits to fully represent it.
For example,




whereas a number whose denominator contains anything else like 1/3 will need an infinite number of bits to represent it exactly.

and so on, so that it has a repeating but non-terminating base-2 representation

Step-by-step explanation:
To prove :
( 1 - sin x ) ( 1 + sin x ) = sec² x
LHS : -
( 1 - sin x ) ( 1 + sin x )
Formula / Identity : -
( a - b ) ( a + b ) = a² - b²
Here,
a = 1
b = sin x
( 1 - sin x ) ( 1 + sin x )
= 1 - sin² x
Identify : -
sin² θ + cos² θ = 1
cos² θ = 1 - sin² θ
Similarly,
1 - sin² x
= cos² x
= RHS
Hence verified.
After 3 hours.
working;
after 3 hours, Terry will have completed 15 hours + 10*3 hours=45 tasks
Susan will have completed 9+ 12*3hours= 45 tasks
Answer:
0 (zero)
Step-by-step explanation:
Plug in the variable for -4 and solve
y= 2(-4)2-4(-4)
y= -8(2)-4(-4)
y=-16+16
y=0