Speed = Distance / Time
Distance = 5t^4 - 10t^2+6
Time = t+2
Now:
5t^4 - 10t^2 + 6 | t+2
-5t^4 -10t^3 5t^3 - 10t^2 + 10t - 20
\\\\\ -10t^3-10t^2+6
+10t^3+20t^2
\\\\\\\ 10t^2+6
-10t^2-20t
\\\\\ -20t+6
+20t+40
\\\\\ 46
<span>C. 5t^3-10t^2+10t-20+(46)/(t+2))</span>
Answer:
Mult by 10000
Step-by-step explanation:
67 deka to centi = 67000 thus mult by 10000 is answer.
Answer:
D
Step-by-step explanation:
We can test each pair making each ratio into its simplest form.
For A 2/3 is already in its simplest form and 9/15=3/5. they are not equivalent.
For B, 5/8 is already in its simplest form and 15/21=5/7. they are not equivalent.
For C, 3/12=1/4, and 6/18=1/3. They are not equivalent.
For D, 4/10=2/5, and 12/30=2/5. They are equivalent.
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
