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UNO [17]
3 years ago
5

Is -18/6 rational integer and whole number​

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

Rational

Step-by-step explanation:

A rational number is a number expressed as a fraction. So the number could be a mixed fraction, improper fraction, decimal, or percentage.

Hope This Helps :)

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PLEASE HELP WILL GIVE BRAINLIEST ANSWER!!
andreyandreev [35.5K]
Speed = Distance / Time

Distance = 5t^4 - 10t^2+6

Time = t+2

Now:

 5t^4 - 10t^2 + 6         | t+2
-5t^4 -10t^3                 5t^3 - 10t^2 + 10t - 20
 \\\\\ -10t^3-10t^2+6
       +10t^3+20t^2
        \\\\\\\ 10t^2+6
                -10t^2-20t
                 \\\\\ -20t+6
                      +20t+40
                       \\\\\ 46

<span>C. 5t^3-10t^2+10t-20+(46)/(t+2))</span>
3 0
2 years ago
Which statement explains Joni’s error?
Law Incorporation [45]

Answer:

Mult by 10000

Step-by-step explanation:

67 deka to centi = 67000 thus mult by 10000 is answer.

7 0
2 years ago
Which pair represents equivalent ratios?
TEA [102]

Answer:

D

Step-by-step explanation:

We can test each pair making each ratio into its simplest form.

For A 2/3 is already in its simplest form and 9/15=3/5. they are not equivalent.

For B, 5/8 is already in its simplest form and 15/21=5/7. they are not equivalent.

For C, 3/12=1/4, and 6/18=1/3. They are not equivalent.

For D, 4/10=2/5, and 12/30=2/5. They are equivalent.

5 0
1 year ago
Read 2 more answers
Keith earns $42.00 in 3 hours. How much would he earn in 10 hours? A. $135.00 B. $140.00 C. $84.00 D. $112.00
xeze [42]
The answer is B. $140
7 0
2 years ago
Read 2 more answers
1. Kalena was asked to prove ifx(x - 1)(x + 1) = x3 - X represents a polynomial identity. She
Verdich [7]

Answer:

C. Kalena made a mistake in Step 3. The justification should state: -x²

+ x²

Step-by-step explanation:

Given the function x(x - 1)(x + 1) = x3 - X

To justify kelena proof

We will need to show if the two equations are equal.

Starting from the RHS with function x³-x

First we will factor out the common factor which is 'x' to have;

x(x²-1)

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;

a²-b² = (a+b)(a-b) hence;

Factorising x²-1 using the difference of two square will give;

x(x+1)(x-1)

Factorising x(x+1) gives x²+x, therefore

x(x+1)(x-1) = (x²+x)(x-1)

(x²+x)(x-1) = x³-x²+x²-x

The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²

6 0
3 years ago
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