Question

PLZ help asap :-/............................ ​

Answer 1

Explanation:

[16]

$\underline{\boxed{\large{\bf{Option \; A!! }}}}$

Here,

• $\rm { R_1}$ = 2Ω
• $\rm { R_2}$ = 2Ω
• $\rm { R_3}$ = 2Ω
• $\rm { R_4}$ = 2Ω

We have to find the equivalent resistance of the circuit.

Here, $\rm { R_1}$ and $\rm { R_2}$ are connected in series, so their combined resistance will be given by,

$\longrightarrow \rm { R_{(1,2)} = R_1 + R_2}$

$\longrightarrow \rm { R_{(1,2)} = (2 + 2) \; Omega}$

$\longrightarrow \rm { R_{(1,2)} = 4 \; Omega}$

Now, the combined resistance of $\rm { R_1}$ and $\rm { R_2}$ is connected in parallel combination with $\rm { R_3}$, so their combined resistance will be given by,

$\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \dfrac{1}{R_{(1,2)}} + \dfrac{1}{R_3} }$

$\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1}{4} + \dfrac{1}{2} \Bigg ) \;\Omega}$

$\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1 + 2}{4} \Bigg ) \;\Omega}$

$\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{3}{4} \Bigg ) \;\Omega}$

Reciprocating both sides,

$\longrightarrow \rm {R_{(1,2,3)}= \dfrac{4}{3} \;\Omega}$

Now, the combined resistance of $\rm { R_1}$, $\rm { R_2}$ and $\rm { R_3}$ is connected in series combination with $\rm { R_4}$. So, equivalent resistance will be given by,

$\longrightarrow \rm {R_{(1,2,3,4)}= R_{(1,2,3)} + R_4}$

$\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4}{3} + 2 \Bigg ) \; \Omega}$

$\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4 + 6}{3} \Bigg ) \; \Omega}$

$\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{10}{3} \Bigg ) \; \Omega}$

$\longrightarrow \bf {R_{(1,2,3,4)}= 3.33 \; \Omega}$

Henceforth, Option A is correct.

_________________________________

[17]

$\underline{\boxed{\large{\bf{Option \; B!! }}}}$

Here, we have to find the amount of flow of current in the circuit. By using ohm's law,

$\longrightarrow$ V = IR

$\longrightarrow$ 3 = I × 3.33

$\longrightarrow$ 3 ÷ 3.33 = I

$\longrightarrow$ 0.90 Ampere = I

Henceforth, Option B is correct.

____________________________

$\tt \purple{Hope \; it \; helps \; you, Army! \heartsuit }$