<span>The range of an object thrown at a velocity v with an angle of elevation 45 degrees is S = v^2/g
100 = v^2/g
=> v^2 = 100*g
In the same throw, the maximum height of the ball can be derived from the equation v^2 - u^2 = 2*g*h
It is is h = =
= 50 metres</span>
