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velikii [3]
3 years ago
5

A cricketer can throw a ball to a maximum horizontal distance of 100m.How much high above the ground can he throw same ball

Physics
1 answer:
rosijanka [135]3 years ago
5 0
<span>The range of an object thrown at a velocity v with an angle of elevation 45 degrees is S = v^2/g 100 = v^2/g => v^2 = 100*g In the same throw, the maximum height of the ball can be derived from the equation v^2 - u^2 = 2*g*h It is is h = = = 50 metres</span>
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Answer:

correct option is B. 1.39

Explanation:

given data

angle of incidence (θ) = 54.2 degrees

to find out

index of refraction of the glass

solution

we know that here reflected beam is completely polarized

so angle of incidence = angle of polarized    ....................1

for reflective index we apply here Brewster law that is

μ = tan(θ)     ...............2

put here θ value we get

μ = tan(54.2)

μ = 1.386

so correct option is B. 1.39

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3 years ago
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Nadya [2.5K]

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B. How much work was done to lift the beam?

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The displacement is still 100 ft since 200 – 100 = 100 ft, hence the work done is still similar in B which is:

<span>Work = 50,000 lbf * ft</span>

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