Answer:
The time it takes the ball to stop is 0.021 s.
Explanation:
Given;
mass of the softball, m = 720 g = 0.72 kg
velocity of the ball, v = 15.0 m/s
applied force, F = 520 N
Apply Newton's second law of motion, to determine the time it takes the ball to stop;

Therefore, the time it takes the ball to stop is 0.021 s.
Density: g/mL, kg/cubic meter
Volume: L, teaspoon
Mass: g, MeV/sq. C