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3 years ago

The ability of matter to easily combine chemically with other substances is know as?

2 answers:

8 0

Answering the question, the ability of matter to easily combine chemically with other substances is called Reactivity.

Reactivity is one of the chemical properties of matter, which implies that matter can combine chemically with other substances.

However, some types of matter can be highly reactive and some can be highly unreactive.

For example, one of the kinds of matter that can be highly reactive is potassium. If you add pea-sized of potassium into a small quantity of water, the reaction will be highly explosive.

Another example is iron: iron is also extremely reactive with oxygen.

<h2>Further Explanation</h2>

Matter can be seen everywhere, it is anything that has mass and can occupy space (volume). Matter can be in different forms which include solid, liquid and gas.

Also, matter is categorized based on its physical and chemical properties which have been tested and verified.

Some of the physical properties of matter can be seen with the naked eyes while some can only be seen through experiments.

However, inflammability is also one of the chemical properties of matter, which implies that matter can burn.

Matter combines with oxygen when it burns and also transforms into different substances such as aches, carbon dioxide, water vapor and other kinds of gases.

Therefore, the ability of matter to easily combine chemically with other substances is called reactivity.

LEARN MORE:

What is the definition of matter? What is matter? brainly.com/question/12632033
What are some classification of matter? brainly.com/question/1915881

KEYWORDS:

reactivity
inflammability
chemical properties
matter
mass
volume
solid
liquid
gas

skelet666 [1.2K]3 years ago

4 0

Reactivity is the ability of matter that allows it to easily chemically combine with other substances.

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The speed of the heavier block is $v_{3x} = 3.55~m/s$ .

(b) The smaller block goes up to 0.69 m.

Explanation:

We will divide this question into three parts: Part A is for the smaller mass from the top of the incline to the collision. Part B is the collision. And Part C is for the smaller mass from the bottom to the highest point it can achieve.

In order to solve this question, I will assume that the smaller mass is initially at rest.

Part A:

We will use conservation of energy.

$K_1 + U_1 = K_2 + U_2\\0 + mgh = \frac{1}{2}mv_1^2 + 0\\(2.2)(9.8)(3.6) = \frac{1}{2}(2.2)v_1^2\\v_1 = 8.4 ~m/s$

This is the speed of the smaller mass just before the collision. The velocity of the mass is directed 30° above horizontal, since the mass is sliding down the incline.

Part B:

Momentum is a vector identity, so the x- and y-components of momentum are to be investigated separately. Since the collision occurs at the horizontal surface, only the x-component of momentum is conserved.

$P_1 = P_2\\mv_{1x} = mv_{2x} + Mv_{3x}\\(2.2)(8.4\cos(30^\circ)) = (2.2)v_{2x} + (6.8)v_{3x}\\16 = 2.2v_{2x} + 6.8v_{3x}$

During the collision kinetic energy is also conserved. Since kinetic energy is a scalar quantity, we don't have to separate its components.

$K_{initial} = K_{final}\\\frac{1}{2}mv_1^2 = \frac{1}{2}mv_{2}^2 + \frac{1}{2}Mv_{3x}^2\\(2.2)(8.4)^2 = (2.2)v_{2}^2 + (6.8)v_{3x}^2\\155.23 = 2.2v_{2}^2 + 6.8v_{3x}^2$