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3 years ago

Which substances in the simulation have particles that are only atoms?

2 answers:

7 0

All matter is made of particles; these can be single atoms or atoms chemically joined to make molecules. Using this fact, matter can be classified into three broad groups: elements, compounds and mixtures. In an element, all the atoms are of the same type. If more than one type of atom is chemically joined, then a compound has been formed. If more than one type of atom or molecule is contained in the same substance, and the particles aren't chemically joined, this is a mixture.

AnnZ [28]3 years ago

6 0

In the simulation, neon and argon have particles that are single atoms. On the other hand, each particle of oxygen is made of two atoms of the same kind.

Hope this helps :)

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Madison lives near the ocean. She’s formed a hypothesis that increased concentrations of salt in the air speeds the corrosion of

kirill [66]

The variables that Madison will have to deal with to test her hypothesis that increased concentrations of salt in the air speeds the corrosion of certain metals are as follows:

Independent variable: concentration of salt
Dependent variable: corrosion of metal

<h3>What are independent and dependent variables?</h3>

In an experiment, the independent variable is the variable that is changed or manipulated in a series of experiments.

On the other hand, a dependent variable is that outcome measured to see the effectiveness of the treatment.

According to this question, Madison makes an hypothesis that an increased concentrations of salt in the air speeds the corrosion of certain metals, the variables she should look out for are as follows:

Independent variable: concentration of salt
Dependent variable: corrosion of metal

Learn more about variables at: brainly.com/question/1479694

#SPJ1

7 0

2 years ago

The following table lists the work functions of a few common metals, measured in electron volts. Metal Φ(eV) Cesium 1.9 Potassiu

Citrus2011 [14]

A. Lithium

The equation for the photoelectric effect is:

$E=\phi + K$

where

$E=\frac{hc}{\lambda}$ is the energy of the incident light, with h being the Planck constant, c being the speed of light, and $\lambda$ being the wavelength

$\phi$ is the work function of the metal (the minimum energy needed to extract one photoelectron from the surface of the metal)

K is the maximum kinetic energy of the photoelectron

In this problem, we have

$\lambda=190 nm=1.9\cdot 10^{-7}m$ , so the energy of the incident light is

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.9\cdot 10^{-7} m}=1.05\cdot 10^{-18}J$

Converting in electronvolts,

$E=\frac{1.05\cdot 10^{-18}J}{1.6\cdot 10^{-19} J/eV}=6.5 eV$

Since the electrons are emitted from the surface with a maximum kinetic energy of

K = 4.0 eV

The work function of this metal is

$\phi = E-K=6.5 eV-4.0 eV=2.5 eV$

So, the metal is Lithium.

B. cesium, potassium, sodium

The wavelength of green light is

$\lambda=510 nm=5.1\cdot 10^{-7} m$

So its energy is

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5.1\cdot 10^{-7} m}=3.9\cdot 10^{-19}J$

Converting in electronvolts,

$E=\frac{3.9\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.4 eV$

So, all the metals that have work function smaller than this value will be able to emit photoelectrons, so:

Cesium

Potassium

Sodium

C. 4.9 eV

In this case, we have

- Copper work function: $\phi = 4.5 eV$

- Maximum kinetic energy of the emitted electrons: K = 2.7 eV

So, the energy of the incident light is

$E=\phi+K=4.5 eV+2.7 eV=7.2 eV$

Then the copper is replaced with sodium, which has work function of

$\phi = 2.3 eV$

So, if the same light shine on sodium, then the maximum kinetic energy of the emitted electrons will be

$K=E-\phi = 7.2 eV-2.3 eV=4.9 eV$

7 0

4 years ago

True or false nodes and antinodes occur in longitudinal waves

Vlad [161]

I believe it is false because longitudinal waves travel parallel to the vibration

8 0

3 years ago

10)A car is moving from rest and attained a velocity of 80 m/s. Calculate the

Mashcka [7]

Explanation:

the velocity graph of a ball mass 20mg moving along a straight line

5 0

4 years ago

Read 2 more answers

A 2 200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.20 m before coming into contact

Kisachek [45]

Answer:

669042 N upward

Explanation:

$W_g$ = Work done by gravity on pile driver

$W_b$ = Work done by beam

u = Initial velocity

v = Final velocity

m = Mass of pile driver = 2200 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height the pile driver falls = 4.2 m

d = Bend in beam = 14 cm

Total work done = Change in Kinetic energy

$W_g+W_b=\frac{1}{2}m(v^2-u^2)\\\Rightarrow mg(h+d)+Fd=0\\\Rightarrow F=-\frac{mg(h+d)}{d}\\\Rightarrow F=-\frac{2200\times 9.81(4.2+0.14)}{0.14}\\\Rightarrow F=-669042\ N$

The force the beam exerts on the pile driver while the pile driver is brought to rest is 669042 N upward

8 0

3 years ago