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Digiron [165]
3 years ago
12

Which expression is equal to 45x4-7: 4-2

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

173

Step-by-step explanation:

45(4)-7

180-7

173

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Please help please please please help
Kipish [7]

Answer:

In the image attached , point G would be the best location for the amphitheatre.


Step-by-step explanation: The developer in order to find the best location for the amphitheatre, needs to find the centroid of the triangle shaped city.

Centroid can be find out easily by finding out the intersection points of all the medians. So we find it by joining TOWN A to midpoint of TOWN B and C , TOWN B to midpoint of TOWN A and C , TOWN C to midpoint of TOWN A and B. And we can observe where these three lines meet is our required point G and also the best location for amphitheatre.


8 0
4 years ago
This is the question
vesna_86 [32]

Hey there!

The answers to your question are C, D, and E

If there are repeats in the X column, then it's not a function. If there are no repeats, then it is! If there are repeats in the Y column, that's ok, but there cannot be repeats in the X column.

Hope this helps! If you need any other help, just tell me!

6 0
3 years ago
Kirby made contributions to roth ira
yawa3891 [41]
Details? you need to add the whole question
6 0
3 years ago
Y=2x-10 substitution <br> Y=4x
Arada [10]
X=5
 Work:

y=2x-10
4x=2x-10
2x=10, then divide 2x on each side
x=5
4 0
4 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
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