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ollegr [7]
3 years ago
11

numA = 2 numB = 3 if numA == 2 or numB == 2: print("yes") elif numA == 2 and numB == 3: print("no") Output:

Computers and Technology
2 answers:
vagabundo [1.1K]3 years ago
8 0

Because of the or keyword in the if statement, only one of the conditions has to be true.

The if statement is true if numA equals 2 or numB equals 2, and numA does equal 2, therefore, the output is yes.

Slav-nsk [51]3 years ago
7 0

Answer:

yes

Explanation:

just took the quiz

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Discuss any five positive and five Negative impact<br>of ICT on society​
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Answer:

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Explanation:

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4 0
3 years ago
Write a pyhton program to calculate area of a circle?
marta [7]

Answer:

The code to calculate the area of a circle is:

from math import pi

def circleArea(radius):

 if radius > 0:

   return pi * (radius ** 2)

 else:

   return None

if __name__ == '__main__':

 radius = 5

 print("Radius: {} Area: {}".format(radius,circleArea(radius)))

Explanation:

A detailed explanation of each line of code is given below.

#Define the number pi used to calculate the area

from math import pi

#We define a function that calculates the area of a circle

def circleArea(radius):

#Check if the radius is valid ( radius > 0) since there aren´t negative radius

 if radius > 0:

#Compute the area formula for a circle \pi * radius^{2}

   return pi * (radius ** 2)

 else:

#Return None if the radius is invalid

   return None

#Run the function we´ve defined

if __name__ == '__main__':

#Define a radius

 radius = 5

#Call the function and parse the radius through it, then print the result

 print("Radius: {} Area: {}".format(radius,circleArea(radius)))

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