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yKpoI14uk [10]
3 years ago
8

***TEN POINTS*** Answer the questions. Deals with functions.

Mathematics
2 answers:
frutty [35]3 years ago
8 0
I don’t know sorry man
forsale [732]3 years ago
5 0

Answer:

f(x) = 250x + 1300

hope this helped and brainliest please (im only ~90 percent sure though, don’t give me brainliest if wrong)

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The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is
Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let X_1 and X_2 denote the sales during week 1 and 2 respectively.

a) Let X=X_1+X_2

Assuming that X_1 and X_2 follows same distribution with same mean and deviation.

E(X)=E(X_1+X_2)=E(X_1)+E(X_2)

E(X)=2\mu = 2(220)=4400

\sigma_X=\sqrt{var(X_1+X_2)}

\sigma_X=\sqrt{2\sigma^2}

\sigma_X=\sqrt{2}\sigma

\sigma_X=230\sqrt{2}

So, X\sim N(4400,230\sqrt{2})

P(X>5000)=1-P(X\leq5000)

P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})

P(X>5000)=1-P(Z\leq1.844)

P(X>5000)=1-0.967

P(X>5000)=0.0321

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

P(X>2000)=1-P(X\leq2000)

P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})

P(X>2000)=1-P(Z\leq-0.87)

P(X>2000)=1-0.1922

P(X>2000)=0.808

Let Y be the number of weeks in which sales exceed 2000.

Now, P(Y\geq 2)

So,  P(Y\geq 2)=P(Y=2)+P(Y=3)

P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3

P(Y\geq 2)=0.37635+0.52692

P(Y\geq 2)=0.90327

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

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From the sum of 3a^2-ab-2b^2 and 2a^2+5ab-3b^2 subtract a^2-3ab-4b^2
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Step-by-step explanation:

Add the first two equations together:

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