The chart is about atomic structure: at the top, the left box is "nucleus" and the right is "electron cloud".
On the left, under nucleus, the two boxes are: "protons" on the right and "neutrons" on the left. Under proton is elements which is given and under neutrons, it is "isotopes".
On the right, under electron cloud, the next box is "electrons" and then the lower box is "ions".
Answer:
the specimen has 11460 years old
Explanation:
if the live sample has as initial amount of Yo C14, the dead sample will have 0.25Yo of C14.
the rate of decay of radiactive matter over time is
- Y(t) = Yo * e (( - t * Ln2 ) / T)
∴ Y(t) = 0.25Yo; T = 5730
⇒ 0.25Yo = Yo * e (( - t * Ln2 ) / 5730 )
⇒ 0.25 = e (( - t * Ln2 ) / 5730 )
⇒ Ln(0.25) = ( - t * Ln2 ) / 5730
⇒ - 7943.466 = - t * Ln2
⇒ 7943.466 / Ln2 = t
⇒ t = 11460 year
Answer:
330.95K
Explanation:
V₁ = 1.2L
T₁ = 25°C = (25 + 273.15)K = 298.15K
P₁ = 1.0 atm
P₂ = 0.74 atm
V₂ = 1.8L
T₂ =?
From combined gas equation,
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Solve for T₂
T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)
T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)
T₂ = 397.1358 / 1.2
T₂ = 330.9465K
T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C
Answer:
pH = 4.4
Explanation:
pH = -log[H₃O⁺]
= -log(4.3 × 10⁻⁵)
pH = 4.37 = 4.4
I'm actually learning this in my chemistry class right now lol. Hope this helps though. :)
