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SVEN [57.7K]
3 years ago
10

What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20°c.) (1 poi

nt) 17 g 34 g 68 g 6800 g?
Chemistry
1 answer:
Solnce55 [7]3 years ago
5 0
The answer is 68g
hope this helps!!
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The process by which molecules of water vapor in the air become liquid water answers
Musya8 [376]
I believe that is condensation
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Why is graphite used as a lubricant
Korvikt [17]

There are weaker covalent bonds between these layers, hence they can easily slide over each other. Due to this, it is a lubricant, since the layers slide over each other so easily. ... Graphite is a mineral made of loosely bonded sheets of carbon atoms, giving it a slippery texture that makes it a very effective lubricant.

6 0
2 years ago
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A 126.1-gram block of granite at 92.6°C is dropped into a tub of water at 24.7°C in an isolated system. The final temperature of
Romashka-Z-Leto [24]

The granite block transferred <u>4080 J</u> of energy, and the mass of the water is <u>35.8 g</u>.

1. <em>Energy from granite block </em>

The formula for the heat (<em>q</em>) transferred is

<em>q = mC</em>Δ<em>T</em>

<em>m</em> = 126.1 g; <em>C</em> = 0.795 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C - 92.6 °C = -40.7 °C

∴ <em>q</em> = 126.1 g × 0.795 J·°C⁻¹g⁻¹ × (-40.7 °C) = -4080 J

The granite block transferred 4080 J.

2. <em>Mass of water </em>

<em>q = mC</em>Δ<em>T </em>

<em>m = q</em>/(<em>C</em>Δ<em>T</em>)

<em>q </em>= 4080 J; <em>C</em> = 4.186 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C – 24.7 °C = 27.2 °C

∴ <em>m</em> = 4080 J/(4.186 J·°C⁻¹g⁻¹ × 27.2 °C) = 35.8 g

The mass of the water is 35.8 g.

7 0
3 years ago
How many atoms are in 3.5 moles of He?
Volgvan

Answer:

The answer is 2.107 × 10²⁴ He atoms

Explanation:

To find the number of atoms given the number moles we use the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 3.5 × 6.02 × 10²³

We have the final answer as

<h3>2.107 × 10²⁴ He atoms</h3>

Hope this helps you

4 0
2 years ago
Which is true about relative dating?
AleksAgata [21]

it's the last one because it's depended on the rock layers

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