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tigry1 [53]
3 years ago
5

Lincoln weighs 400 newtons. What’s his mass rounded to the nearest kilogram? Assume that acceleration due to gravity is 9.8 N/kg

.
Physics
2 answers:
Yanka [14]3 years ago
6 0
Weight equals mass times gravitational acceleration=400N, so mass=400/9.8=41kg approx.
Serggg [28]3 years ago
6 0

Answer:

41 k

Explanation:

Use the formula for weight: W = m × g. Rearrange the formula to solve for m:

m = W ÷ g.

Substitute W = 400 newtons and g = 9.8 N/kg into the formula. Then divide:

m = 400 N ÷ 9.8 N/kg

40.8 kg.

Rounded to the nearest kilogram, Lincoln has a mass of 41 kilograms.

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Which of the following type of personal debts is usually considered wise and justified? A. credit card purchases of luxuries tha
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C. Money to pay off other debts and interest

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How many electrons are in 204 C of charge?
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The mass number 204 – 82 protons = 122 neutrons

Explanation:

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3 years ago
A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside
neonofarm [45]

Answer:

\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}, level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

\dot V_{in} - \dot V_{out} = \frac{dV_{tank}}{dt}

\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt}  = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}

By replacing all known variables:

\frac{dh}{dt} = \frac{(0.3 ft)^{2}\cdot (5 \frac{ft}{s} ) - (0.4 ft)^{2} \cdot (2 \frac{ft}{s} )}{(10 ft)^{2}}\\\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}

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6 0
3 years ago
A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pus
Alchen [17]

Answer:

<h3>2,321.62Joules</h3>

Explanation:

The formula for calculating workdone is expressed as;

Workdone = Force * Distance

Get the force

F = nR

n is the coefficient of friction = 0.5

R is the reaction = mg

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R = 450.8N

F = 0.5 * 450.8

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<em>Hence the amount of work done is 2,321.62Joules</em>

3 0
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