B. Energy enters and exits the system matter does not
Explanation:
In thermodynamics, there are three types of system:
- Open system: it is a system that exchanges both matter and energy with the surroundings - an example is an open bottle
- Closed system: it is a system that exchanges only matter with the surroundings, while energy cannot enter and exit the system - an example is a closed bottle (air cannot enter/exit the bottle, but heat can be exchanged through the walls of the bottle)
- Isolated system: it is a system that cannot exchange matter or energy with the surroundings - an example is a sealed thermic container (heat cannot pass through the walls)
In this problem, we are asked to identify which statement best describes the island food web as a closed system: based on the definitions above, we can say that the correct option is
B. Energy enters and exits the system matter does not
Learn more about thermodynamics:
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Answer:
D. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
Explanation:
The above statement is true due to the fact that, the weight and masses of the individual are same in direct comparison with the distance to their center of gravity.<em> If the weight and masses are not same, then there would have been a significant difference between the two planet.</em>
ANOTHER RUNNING DOG
Explanation:
In the given question it is to find a suitable reference point to describe the motion of dog. Here I could suggest that it is better to compare the dog with another running dog to create the relative speed difference to get a reliable motion variation.
Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to another dog which is already in motion.
Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with another dog running.
Answer:
232
U
92
Explanation:
mass number=protons add neutrons
Atomic number= amount of protons
Answer:
(a) q=3.07 nC
(b) σ=17 nC/m²
Explanation:
Given data
Radius r=0.12m
Potential V=230 V
To find
(a) Charge q
(b) Charge density σ
Solution
For Part (a)
As we know that potential is:
Substitute the given values
For Part (b)
The charge density is given by:
σ=q/(4πr²)
Substitute the given values and value of q to find charge density
So
σ=17 nC/m²
