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Readme [11.4K]
3 years ago
11

Briefly describe the life, successes, and failures of Emperor Justinian.

Biology
1 answer:
Mariana [72]3 years ago
5 0

Who he was?

Justinian I served as emperor of the Byzantine Empire from 527 to 565. Justinian is best remembered for his work as a legislator and codifier. During his reign, Justinian reorganized the government of the Byzantine Empire and enacted several reforms to increase accountability and reduce corruption. He also sponsored the codification of laws known as the Codex Justinianus (Code of Justinian) and directed the construction of several important cathedrals, including the Hagia Sophia.

Success

He conquered the barbarian Saxons after thirty years. He constructed a wonderful palace Aachen. He made good laws and selected judges to see that the laws were enforced. Justinian made improvements on the capitol, Constantinople.

Failures

•Wasted away the filled treasury he had inherited.

•Supported the Blue faction in his early years.

•Failed to act as even-handed patron of both the Blues and the Greens.

•Acted like a tyrant during the Nika Riots.

•Was too indecisive in the Nika Riots.

•Forced prostitutes into monasteries.

•Married a low-born actor for "love"

Hope it helps... pls mark brainliest

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Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

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3 years ago
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Answer:

No it hasn't been recommended by a doctor.

Explanation:

This is considered pseudoscience because there is no proof that it has been scientifically proven.

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Answer:

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Hopefully this was helpful! :)

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Answer:

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J'espère t'avoir aidé, bonnes études !

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