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3 years ago

HELP IM BEING TIMED, ILL MARK BRAINLIEST.

Mathematics

2 answers:

Delicious77 [7]3 years ago

5 0

Answer:

i think its b but im sorry if im wrong

Step-by-step explanation:

Anna35 [415]3 years ago

4 0

Answer:

the answer is b: StartFraction 1 Over x Superscript 21 Baseline y Superscript 12 Baseline EndFraction

Step-by-step explanation:

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To approximate the length of a lake, a surveyor starts at one end of the lake and walks 245 yards. He then turns 110 and walks 2

kolezko [41]

Answer:

Surveying To approximate the length of a marsh, a surveyor walks 250 meters from point to point , then turns and walks 220 meters to point (see figure). Approximate the length of the marsh.

hope it helped

Step-by-step explanation:

8 0

2 years ago

Solve the following equations then place the correct number in the box provided.

alexira [117]

The answer is negative two I believe so if I’m right I’m not 100% sure on this one

6 0

3 years ago

How do I make 9.076 turn into expandedform

Contact [7]

Answer:

9 + 0.0 + 0.07 + 0.006

Step-by-step explanation:

9 + 0.0 + 0.07 + 0.006

4 0

2 years ago

A news station in oregon recorded that the low temperature for 5 days were -3,-2,2,2, and 6.what was the average temperature for

emmainna [20.7K]

[ (- 3) + (-2) + 2 + 2 + 6 ] / 5 = 5 / 5 = 1.

6 0

3 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago