Equation is as follow,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Oxidation:
3 CO → 3 CO₂
Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,
3 CO → 3 CO₂ + 6 e⁻
Reduction:
Fe₂O₃ → 2 Fe
Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,
Fe₂O₃ + 6e⁻ → 2 Fe
Result:
Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.
VALENCE ELECTRONS DETERMINE CHEMICAL PROPERTIES BECAUSE WHEN SAME ELEMENT REACT WITH DIFFERENT ELEMENTS THEN DIFFERENT COMPOUNDS ARE FORMING.FOR EXAMPLE HYDROGEN BOND WITH OXYGEN THEY FORM WATER AND WHEN HYDROGEN BOND WITH CHLORINE THEY FORM HCL WHICH SHOWS DIFFERENT PROPERTIES FROM WATER.
100 HZ the drum will move up and down 30 each second
Answer:
4.57 × 10⁶ nanometers
Explanation:
In this problem we are asked to convert between two units i.e. a meter into nanometer. In sciences, the different units are used for a same quantity (achieved by multiplying conversion factors) to get rid of very small values and get a readable and intelligible values.
For Example:
In given statement the value of small distance is 4.5 × 10⁻³ meter the real number form of this number is 0.00457. Hence, this number can be converted to a very large number by multiplying it with 10⁹ or 1000000000. Hence,
4.5 × 10⁻³ × 1.0 × 10⁹ = 4.57 × 10⁶
Or,
4.5 × 10⁻³ meters = 4.57 × 10⁶ nanometers
Although the quantity is the same for same units but the number has changed.
Answer:
For the first reaction the reagents are: MgCl2 and Na2CO3
For the second reaction the reagents are: Na2HPO4 and CaCl2
Explanation:
Precipitation reactions lie in the production of a compound that is not soluble, which is called a precipitate, this precipitate is produced when two different solutions are combined, each of which will contribute an ion for the formation of the precipitate. In the first reaction you have:
MgCl2 + Na2CO3 = MgCO3 + 2 NaCl
Type of reaction: double displacement
The second reaction is as follows:
4Na2HPO4 + 3CaCl2 → Ca3 (PO4) 2 + 2NaH2PO4 + 6NaCl
It is the reaction of sodium hydrochlorophosphate and calcium chloride
