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3 years ago

Based on Table F, which compound is least soluble in water?

Chemistry

1 answer:

Stella [2.4K]3 years ago

5 0

It would be c plz give me brainlessly hope i’m correct

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Determine the molar mass of :<br><br> 1. H20<br> 2. Co2<br> 3.NaCl

taurus [48]

Answer:

1 is the chemical formula for water, meaning that each of its molecules contains one oxygen and two hydrogen atoms.

2 a colorless, odorless gas produced by burning carbon and organic compounds and by respiration. It is naturally present in air (about 0.03 percent) and is absorbed by plants in photosynthesis.

3 Chemical abbreviation for sodium chloride (table salt)

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3 years ago

Read 2 more answers

What were the procedures and outcome of this experiment? Contrast the actual outcome with Rutherford’s anticipated outcome.

jarptica [38.1K]

Be more specific, I could possibly find the asnwer you're looking towards.

6 0

3 years ago

To convert from Mass A to moles of B in stoichiometry problems, the following steps are followed:

WINSTONCH [101]

I think a is the answer

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4 years ago

A compound contains 39.0% potassium, 1.01% hydrogen, 12.0% carbon and 47.9% oxygen. Find its empirical formula

Ipatiy [6.2K]

Answer:

Empirical formula is KHO₃C.

Explanation:

Given data:

Percentage of potassium = 39.0%

Percentage of hydrogen = 1.01%

Percentage of carbon = 12.0%

Percentage of oxygen = 47.9%

Empirical formula = ?

Solution:

Number of gram atoms of K = 39.0/ 39 = 1

Number of gram atoms of H = 1.01 / 1.01 = 1

Number of gram atoms of O = 47.9 / 16 = 3

Number of gram atoms of C = 12 / 12 = 1

Atomic ratio:

K : H : O : C

1/1 : 1/1 : 3/1 ; 1/1

1 : 1 : 3 : 1

K : H : O :C = 1: 1 : 3 : 1

Empirical formula is KHO₃C.

4 0

4 years ago

Assume the volume of the crew cabin is 74,000 L. The pressure is maintained at around 1.00 atm, ideally with an 80% nitrogen and

hjlf

Answer:

The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles

Explanation:

The given parameters are;

Volume of the crew cabin = 74,000 L

Pressure of the crew cabin = 1.00 atm

Percentage of nitrogen in the mixture of gases in the cabin = 80%

Percentage of oxygen in the mixture of gases in the cabin = 20%

Temperature of the cabin = 20°C = 293.15 K

Therefore, volume of oxygen in the crew cabin = 20% of 74,000 L

Hence, volume of oxygen in the crew cabin = $\frac{20}{100} \times 74,000 \, L = 14,800 \, L$

From the universal gas equation, we have;

$n = \frac{P \times V}{R \times T}$

Where:

n = Number of moles of oxygen

P = Pressure = 1.00 atm

V = Volume of oxygen = 14,800 L

T = Temperature = 293.15 K

R = Universal Gas Constant = 0.08205 L·atm/(mol·K)

Plugging in the values, we have;

$n = \frac{1 \times 14,800 }{0.08205 \times 293.15 } = 615.309 \, moles$

The number of moles of oxygen present in the crew cabin at any given time = 615.309 moles.

3 0

4 years ago