Answer:
0.25M HCl
Explanation:
The reaction of HCl with NaOH is:
HCl + NaOH ⇄ H₂O + NaCl
<em>Where 1 mole of HCl reacts per mole of NaOH</em>
The end point was reached when the student added:
0.0500L × (0.1mol / L) = 0.00500 moles of NaOH
As 1 mole of HCl reacted per mole of NaOH, moles of HCl present are:
<em>0.00500 moles HCl</em>
The volume of the sample of hydrochloric acid was 20.0mL = 0.0200L, and concentration of the sample is:
0.00500 mol HCl / 0.0200L = <em>0.25M HCl</em>
Answer: SO₂ + H₂O → HSO₃ ⁻ + H⁺
Justification:
1) Ionization means formation of ions.
2) Ions are species that are not neutral, they are charged, in virtue of having less or more electrons than protons.
3) Ionization may happen in different environments.
4) Ionic compunds, like Mg(OH)₂ dissociate into ions (ionize) in water. That is the example shown in the fourth option:
Mg(OH)₂ → Mg ²⁺ + 2OH⁻
5) How much a ionic compound dissociates in water (ionize) depends on the Ksp (product solubility constant) which measures the concentrations of the ions that can be in the solution.
6) The Ksp for Mg(OH)₂ is very low, meaning that it will slightly ionize.
7) SO₂ + H₂O forms H₂SO₄, which is a strong acid, meaning that it will ionize fully in water, into the ions HSO₃ ⁻ and H⁺, so the third option is a good example of ionization.
Answer:
2AlCl3 + 3H2SO4 → Al2(SO4)3 + 6HCl
Explanation:
Answer:
2.1056L or 2105.6mL
Explanation:
We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:
Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol
Mass of Na2CO3 = 10g
Mole of Na2CO3 =.?
Mole = mass /molar mass
Mole of Na2CO3 = 10/106
Mole of Na2CO3 = 0.094 mole
Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:
Na2CO3 + 2HCl —> 2NaCl + H2O + CO2
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CO2.
Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.
Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:
1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.
Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L
Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL
SInce earths gravitational force is 9.81, and outer space is less than that, the force decreases
