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fenix001 [56]
3 years ago
7

Which substance is the oxidizing agent in this reaction? fe2o3+3co→2fe+3co2 express your answer as a chemical formula?

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0
Equation is as follow,

                            Fe₂O₃  +  3 CO     →     2 Fe  +  3 CO₂

Oxidation:

                                        3 CO     →     3 CO₂

Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,

                                 3 CO     →     3 CO₂  +  6 e⁻

Reduction:

                                    Fe₂O₃     →     2 Fe

Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,

                                    Fe₂O₃  +  6e⁻     →     2 Fe

Result:
             Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.
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Answer:

Plates sliding past each other cause friction and heat. Subducting plates melt into the mantle, and diverging plates create new crust material. Subducting plates, where one tectonic plate is being driven under another, are associated with volcanoes and earthquakes.

Explanation:

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How are the formulas and names of ionic compounds written
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Put the cation (a positive ion, the metal in this case,) without changing anything, then the nonmetal, or anion. For the nonmetal, change the ending to -ide. For example, if you have potassium and chlorine, you would have potassium chloride. Hope this helps!
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Which phrase provides the best definition of a landform region?
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Explanation:

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3 years ago
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Combined gas law, PLEASE HELP!
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You correctly said that you need the combined gas law. 

combine gas law----> P1V1/T1= P2V2/T2

P1= ?
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5 0
2 years ago
A 75.0 mL 75.0 mL aliquot of a 1.70 M 1.70 M solution is diluted to a total volume of 278 mL. 278 mL. A 139 mL 139 mL portion of
Vlada [557]

Answer:

0.210 M

Explanation:

<em>A 75.0 mL aliquot of a 1.70 M solution is diluted to a total volume of 278 mL.</em>

In order to find out the resulting concentration (C₂) we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

1.70 M × 75.0 mL = C₂ × 278 mL

C₂ = 0.459 M

<em>A 139 mL portion of that solution is diluted by adding 165 mL of water. What is the final concentration? Assume the volumes are additive.</em>

Since the volumes are additive, the final volume V₂ is 139 mL + 165 mL = 304 mL. Next, we can use the dilution rule.

C₁ × V₁ = C₂ × V₂

0.459 M × 139 mL = C₂ × 304 mL

C₂ = 0.210 M

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3 years ago
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