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Free_Kalibri [48]
3 years ago
6

1. Which of the following compounds is most likely to exist as a covalent molecule? O NaBr O KNO, O Bel, C O CH_NH2?​

Chemistry
1 answer:
DIA [1.3K]3 years ago
6 0

Answer:

nabeo

Explanation:

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write a balanced net ionic equation for the following reaction: BaCl2(aq) + H2SO4 (aq) -- BaSO4(s) + HCl (aq)
Fudgin [204]

The  balanced net  equation  for

BaCl2 (aq)  + H2SO4(aq) → BaSO4(s)  + HCl  (aq)  is

 Ba^2+(aq)  +SO4^2- → BaSO4 (s)

 <u><em>Explanation</em></u>

Ionic equation  is a chemical  equation in which  electrolytes  in aqueous  solution are written as dissociated ions.

<u>ionic equation is written using the below steps</u>

Step 1:  <em>write a balanced   molecular equation</em>

 BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s)  +2HCl (aq)

Step 2:   <em>Break all soluble  electrolytes  in to ions</em>

=  Ba^2+ (aq) + 2Cl^-(aq)  + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s)   + 2H^+(aq)  +2Cl^- (aq)


step 3:  <em>cancel the spectator  ions  in both side of equation ( ions which  do not take place in the reaction)</em>

<em> </em><em>    =</em> 2Cl^-  and  2H^+  ions

Step 4: <em>write the final net equation</em>

<em> Ba^2+(aq)  + SO4^2-(aq)→  BaSO4(s</em><em>)</em>

3 0
3 years ago
Read 2 more answers
What is a maximum negative displacement of a wave
AnnZ [28]

The maximum negative displacement of a wave is the same as its amplitude.

As a wave travels through space, its particles are sometimes above the

<em>x</em>-axis (+) and sometimes below it (-).

The maximum displacement from the axis is the <em>amplitude</em> of the wave.

The amplitude of the wave is the <em>same in both the positive and negative directions</em>.

5 0
3 years ago
Ppppoooooooooiiiiiiiiiinnnnnnnnnttttttttssssssss
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3 0
3 years ago
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Need help asap with this chemistry if someone could help me
Burka [1]

Answer:

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

Structure Number Two would likely be the most stable structure.

<h3>2)</h3>
  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

The N atom is the one that is "likely" to be attracted to an anion. See explanation.

Explanation:

When calculating the formal charge for an atom, the assumption is that electrons in a chemical bond are shared equally between the two bonding atoms. The formula for the formal charge of an atom can be written as:

\text{Formal Charge} \\ = \text{Number of Valence Electrons in Element} \\ \phantom{=}-\text{Number of Chemical Bonds} \\\phantom{=} - \text{Number of nonbonding Lone Pair Electrons}.

For example, for the N atom in structure one of the first question,

  • N is in IUPAC group 15. There are 15 - 10 = 5 valence electrons on N.
  • This N atom is connected to only 1 chemical bond.
  • There are three pairs, or 6 electrons that aren't in a chemical bond.

The formal charge of this N atom will be 5 - 1 - 6 = -2.

Apply this rule to the other atoms. Note that a double bond counts as two bonds while a triple bond counts as three.

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

In general, the formal charge on all atoms in a molecule or an ion shall be as close to zero as possible. That rules out Structure number one.

Additionally, if there is a negative charge on one of the atoms, that atom shall preferably be the most electronegative one in the entire molecule. O is more electronegative than N. Structure two will likely be favored over structure three.

<h3>2)</h3>

Similarly,

  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

Assuming that electrons in a chemical bond are shared equally (which is likely not the case,) the nitrogen atom in this molecule will carry a positive charge. By that assumption, it would attract an anion.

Note that in reality this assumption seldom holds. In this ion, the N-H bond is highly polarized such that the partial positive charge is mostly located on the H atom bonded to the N atom. This example shows how the formal charge assumption might give misleading information. However, for the sake of this particular problem, the N atom is the one that is "likely" to be attracted to an anion.

5 0
3 years ago
The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of
timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = 1.83g/cm^3=1.83g/ml

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml

Now we have to calculate the molarity of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0
3 years ago
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