Answer:
x≤ −2/3y + −1/3
Step-by-step explanation:
because...
Step 1: Add -4y to both sides.
6x + 4y + −4y ≤ −2+−4y
6x ≤ −4y −2
Step 2: Divide both sides by 6.
6x/6 ≤ 
x ≤ −2/3y + −1/3
Therefor, the answer is x≤ −2/3y + −1/3
* Hopefully this helps:) Mark me the brainliest:)!!
Answer:
1. 30°
2.90°
3. 12 units
Step-by-step explanation:
I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)
1.
The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.
2.
If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.
3.
Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.
Sorry if this is all dreadfully wrong, and I hope I helped you!
Answer: 2nd option, 3rd option, and the last option are all correct
Answer:
Part a
For the given study, the explanatory variable or independent variable is given as regularity or frequency of exercise. This variable is classify as categorical variable because variable is divided into two categories such as whether participant exercise 5 or more days a week or not.
Part b
For the given study, the response variable or dependent variable is given as frequency of colds. This variable is classified as quantitative variable because we measure the quantities or frequency of number of colds.
Part c
A confounding variable for this research study is given as incidence of upper respiratory tract infections that provides an alternative explanation for the lower frequency of colds among those who exercised 5 or more days per week, compared to those who were largely sedentary. This confounding variable is categorical in nature.
Area of a square is its side length squared...
A=s^2 solving for s...
s=√A
The perimeter of a square is 4 times its side length...
P=4s, and since s=√A
P=4√A, and we are told that A=100 in^2 so
P=4√100
P=4*10
P=40 in
