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gulaghasi [49]
3 years ago
7

Show that the value of cos 30 x tan 60 + sin 30 is an integer

Mathematics
2 answers:
Troyanec [42]3 years ago
7 0

Answer:

ang hirap nang tanong

tatiyna3 years ago
5 0

Answer:

value of cos 30 × tan 60 + sin 30 is an integer...

Step-by-step explanation:

cos 30 =

\frac{ \sqrt{3} }{2}

tan 60 =

\sqrt{3}

sin 30 =

\frac{1}{2}

so, cos 30 × tan 60 + sin 30

\frac{ \sqrt{3} }{2}  \times  \sqrt{3}  +  \frac{1}{2}

=

\frac{3}{2}  +  \frac{1}{2}

=

\frac{4}{2}

=

2

and 2 is an integer , hence we proved that

cos 30 × tan 60 + sin 30 is an integer.

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence interval for the proportion of homeles
MA_775_DIABLO [31]

Answer:

[0.184, 0.266]

Step-by-step explanation:

Given:

Number of survey n =280

Number of veterans = 63

Confidence interval = 90%

Computation:

Probability of veterans = 63/280

Probability of veterans =0.225

a=0.1

Z(0.05) = 1.645 (from distribution table)

Confidence interval = 90%

So,

p ± Z*√[p(1-p)/n]

0.225 ± 1.645√(0.225(1-0.225)/280)

[0.184, 0.266]

4 0
3 years ago
Identify the vertical asymptotes of f(x) = 2 over quantity x squared plus 3 x minus 10.
zysi [14]
The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) =
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x + 5 = 0 => x = - 5
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Answer:
The vertical asymptotes are: x = - 5 and x = 2.
3 0
3 years ago
PLEASE HELP THANKS, Scale factoring
Radda [10]

Answer:

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Step-by-step explanation:

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8 0
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Max is stacking logs at his campground for firewood. After his first load of logs, he has 12 logs on the stack. After his sevent
Natasha2012 [34]

Answer:

Let L(n) be the function that gives the amount of logs stacked after n loads.

L(n) = 12 + 8(n-1)

Step-by-step explanation:

Let L(n) be the function that gives the amount of logs stacked after n loads.

Let's call for the moment the first load as L(0)

L(0)= 12  

Let r be the number of logs carried in each load, then  

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Since L(6) (the seventh load) equals 60, we have

60 = 12 + 6r, and r = 8.

So a function for the number of loads starting from n=0 would be

L(n) = 12 + 8n

If we want to start with n=1, we simply change the variable

L(n) = 12 + 8(n-1) (n=1,2,3,...).

So L(1) = 12, L(2) = 20, L(3) = 28,...L(7) = 60 and so on.

7 0
3 years ago
If 14 is 35% of a value, what is that value?<br> ОА. 40,<br> ОВ. 86<br> Ос. 65<br> OD. 21
antiseptic1488 [7]
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