Answer:
0.0139- frequency of heterozygotes in the population
Explanation:
Let q to the power of 2 represents the frequency of the homozygous recessive (aa) = 1/20000 = 0.00005
This, q = √q^2 = √0.00005 = 0.007
Since p + q = 1
p = 1 - 0.007 = 0.993
Using the formula: p^2 + 2pq + q^2
Where 2pq represents the frequency of the heterozygotes, thing we have
2 x 0.007 x 0.993
= 0.0139
The answer is c) a number and a unit
Answer:
DNA strand = complementary strand
GCAAG = CGTTC
TTACG = AATGC
GATAC = CTATG
CGGAT = GCCTA
DNA strand = mRNA strand
CGATT = GCUAA
GCTTA = CGAAU
GCATC = CGUAG
TTCAT = AAGUA
Explanation: A complementary strand is not the same in base composition and sequence with the template strand. In DNA, anywhere adenine is found in the template strand, thymine is found in the complementary strand and anywhere cytosine is found in the template strand, guanine is found in the complementary strand. But in RNA, anywhere adenine occurs in the DNA template strand, uracil occurs in the mRNA strand, wherever thymine occurs in the DNA template strand, adenine occurs in the mRNA strand and wherever guanine occurs in the DNA template strand, cytosine occurs in the mRNA strand.
Summarily, in DNA adenine pairs with thymine while cytosine pairs with guanine while in mRNA, adenine pairs with uracil, while cytosine pairs with guanine.
The individual will have 42 chromosome
The answer is: energia quimica.
