Answer:
Both of them are Non-Proportional since none are touching 0. I'm not sure if you're looking for Proportionality.
Answer: 0.712
Step-by-step explanation: have a good night :)
Answer:
Step-by-step explanation:


when a=-1/4



case 2.
both numerator and denominator are negative.
![x-3\leq 0\\x\leq 3\\-x+2\leq 0\\-x\leq -2\\x\geq 2\\solution~is~(-\infty,-3)U(-3,3]U[2,\infty)](https://tex.z-dn.net/?f=x-3%5Cleq%200%5C%5Cx%5Cleq%203%5C%5C-x%2B2%5Cleq%200%5C%5C-x%5Cleq%20-2%5C%5Cx%5Cgeq%202%5C%5Csolution~is~%28-%5Cinfty%2C-3%29U%28-3%2C3%5DU%5B2%2C%5Cinfty%29)
I help u and i will tell u the answer and the is A
The asymptotes
X = 2
X = - 2
Y = 2