Answer:
hypotenuse is not a rational number
Step-by-step explanation:
In a Right angled triangle , if a, b are the sides and h be the hypotenuse then relationship between them is given by
=
+ 
Here,
a= 4 in. [Given]
b = 6 in. [Given]
Thus ,
=
+ 
= 16 + 36
= 52.
h =
= 7.21110255......
Clearly, h is not a rational number
Thw sale tax will be $ 418.80 on the book bag
X = 0
<span>6y - 5x = 0 so it intersects x=0 at (0,0)
</span>
<span>x + 3y = 21
</span>so it intersect x=0 at (0,7)
multiply by 2
<span>2x + 6y = 42
subtracting 6y - 5x = 0
7x = 42
x = 6
so the third line intersects w second line at (6,5)
6. area of triangle = 1/2*base*height
= 1/2*7*6
=21
7. volume = volume of 2 cones
cone volume = 1/3*pi*radius^2*height
lower cone: radius=6, height=5
upper cone: radius=6, height=7-5=2
volume = 1/3*pi*6^2*(5+2)
=84pi
=263.89
</span>
9514 1404 393
Answer:
(0, -8), (1, -11), (-1, -5)
Step-by-step explanation:
It is convenient to solve for y and choose values of x.
y = -3x -8 . . . . . subtract 3x from both sides of the equation
Now, any integer value of x you choose will result in an integer value of y. Often, it is convenient to choose values near zero.
x = -1, y = -3(-1) -8 = 3 -8 = -5 . . . . solution: (-1, -5)
x = 0, y = -3(0) -8 = -8 . . . . solution: (0, -8)
x = 1, y = -3(1) -8 = -11 . . . . solution: (1, -11)
Hello!

Recall that:
is equal to
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
