All categories

3 years ago

X (0,6) y (-3,15) what are the slope and y intercept

Mathematics

1 answer:

elena-s [515]3 years ago

4 0

Answer:

y = -3/9x + 6

Step-by-step explanation:

slope = -3/9x

y-intercept = 6

You might be interested in

carter has a collection of 37 coins found while walking home. All of Carter coins are either nickels or dimes. The value of the

LenKa [72]

Answer:

11.9

Step-by-step explanation:

3 0

3 years ago

Judy wants to buy juice boxes at the lowest unit rate. Which is the best

Fudgin [204]

C would be the lowest cost at 91 cents per juice box

5 0

2 years ago

Read 2 more answers

Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0

3 years ago

SOMEONE, PLEASE ANSWER THIS!

IrinaVladis [17]

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6

This cannot be simplified any more than what it is now.

8 0

1 year ago

Read 2 more answers

The distance y in miles traveled by a striped marlin in x hours is shown in the graph. Each ocean creature’s distance in miles i

julsineya [31]

9514 1404 393

Answer:

swordfish

Step-by-step explanation:

The graph shows the marlin travels 50 miles in 1 hour, and 150 miles in 3 hours. These numbers can be compared directly to those given for the tuna (43.5 miles in 1 hour) and the wahoo fish (144 miles in 3 hours).

The speeds of the swordfish and shark are the coefficients of x in their respective equations. The swordfish travels 60 mph, so is faster than the marlin. The shark travels 31 mph, so is slower.

7 0

2 years ago