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Serjik [45]
3 years ago
13

For Babysitting Niki charges a flat fee of $10 plus 15 per hour if we want to know how many hours she work if she gets paid by $

80 which equation is helpful
15x-10=85

10+15x=85

85-10x=15

85x-10=15
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0
The second equation would be the most helpful
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Need answer ASAP <br> *MARKING BRAINLIEST
Luba_88 [7]

Answer:

252 in²

Step-by-step explanation:

Recall area of regular polygon is A= (1/2)*(perimeter)*(apothem)

Area = (1/2)*(63)*(7)

= 252 in²

7 0
3 years ago
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The table shown below shows some values for functions f(x) and g(x). What is/are the solutions for f(x) =g(x)
deff fn [24]

i need this answer too

3 0
3 years ago
A cereal comes in three different package size what is the ratio of the cost of an 8 ounce box to a 16 ounce box of cereal
34kurt

Answer:

5-3 or 3-5

Step-by-step explanation:

8 0
3 years ago
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
Jose equation is -4(x+2) = 8x+16 says to jill “I can solve for the variable in this equation in at least 4 different ways
erastovalidia [21]

Answer:

that is step 1 and step 2 and step3

step 4

Let's solve your equation step-by-step.

−4(x+2)=8x+16

Step 1: Simplify both sides of the equation.

−4(x+2)=8x+16

(−4)(x)+(−4)(2)=8x+16(Distribute)

−4x+−8=8x+16

−4x−8=8x+16

Step 2: Subtract 8x from both sides.

−4x−8−8x=8x+16−8x

−12x−8=16

Step 3: Add 8 to both sides.

−12x−8+8=16+8

−12x=24

Step 4: Divide both sides by -12.

−12x

−12

=

24

−12

x=−2

Answer:

x=−2

6 0
3 years ago
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