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Lelechka [254]
3 years ago
8

Help pleaseeeeeee❗️❗️❗️❗️

Mathematics
2 answers:
navik [9.2K]3 years ago
4 0

Answer: B

Step-by-step explanation: Mr. Inderhees added 5 to each side of the equation for his first step to isolate the <em>x</em> term which in this case is 4x.

So when he added 5 to both sides of the equation, he got 20 = 4x.

Mrac [35]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Mr. Inderhees added 5 to each side of the equation for his first step to isolate the x term which in this case is 4x.

So when he added 5 to both sides of the equation, he got 20 = 4x.Mr. Inderhees added 5 to each side of the equation for his first step to isolate the x term which in this case is 4x.

So when he added 5 to both sides of the equation, he got 20 = 4x.

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Which expression would be equivalent to: Which expression would be equivalent to: \frac{1+b}{2} - 3(a-1)
IrinaVladis [17]

Answer:

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}

Step-by-step explanation:

Given

\frac{1+b}{2} - 3(a-1)

Required

An equivalent expression

\frac{1+b}{2} - 3(a-1)

Take LCM

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}

Open bracket

\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}

Collect like terms

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}

\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}

Hence, an equivalent expression is:

\frac{b- 6a+7}{2}

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