What are the zeros of the function f(x) =x^2-11x+24 ?
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Answer:
m∠ACE = 40°
Step-by-step explanation:
Consider the below figure attached with this question.
Given information: arc BD = 25°, minor arc AB = 115°, and minor arc DE = 115°.
We need to find the measure of ∠ACE.
minor arc AB + minor arc BD + minor arc DE + minor arc AE = 360°
115° + 25° + 115° + minor arc AE = 360°
255° + minor arc AE = 360°
minor arc AE = 360° - 255°
minor arc AE = 105°
The measure of minor arc AE is 105°.
Using Intersecting secants outside the circle theorem
Angle between two secants = (Major arc - Minor arc)
Therefore, the measure of ∠ACE is 40°.
