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lord [1]
3 years ago
10

Help me solve this please​

Physics
1 answer:
Wewaii [24]3 years ago
7 0

Answer:

<h2>option b , 2A</h2>

Explanation:

<h2>V= IR</h2>

thus

<h2>I=V/R</h2>

so putting values we get,

I = 120/ R

for the value of R...

R(series) = R1 + R2 + R3

R= 20 + 20+ 20 = 60 ohm

<h2>R=60ohm</h2>

thus, I=120/60 = 2

Therefore,

<h2>I = 2A</h2>
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An object is thrown vertically and has a speed of 25 m/s when it reaches 1/4 of its maximum height above the ground (assume it s
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Answer:

v_{i} =28.86\frac{ft}{s}

Explanation:

Conceptual analysis

We apply the kinematic formula for an object that moves vertically upwards:

(v_{f} )^{2} =(v_{i} )^{2} -2*g*y

Where:

v_{f} : final speed in ft/s

v_{i} : initial speed in ft/s

g: acceleration due to gravity in ft/s²

y: vertical position at any time in ft

Known data

For v_{f} = 25\frac{ft}{s} ,y=\frac{1}{4} h; where h is the maximum height

for y=h,  v_{f} =0

Problem development

We replace  v_{f} = 25\frac{ft}{s}  , y=\frac{1}{4} h (ft) in the formula (1),

[25^{2} =(v_{i} )^{2} -2*g*\frac{h}{4}   Equation (1)

in maximum height(h): v_{f} =0, Then we replace in formula (1):

0=(v_{i} )^{2} - 2*g*h

2*g*h=(v_{i} )^{2}

h=\frac{(v_{i})^{2}  }{2g}   Equation(2)

We replace (h) of Equation(2) in the  Equation (1) :

25^{2} =(v_{i} )^{2} -2g\frac{\frac{(v_{i})^{2}  }{2g} }{4}

25^{2} =(v_{i} )^{2} -\frac{(v_{i})^{2}  }{4}

25^{2} =\frac{3}{4} (v_{i} )^{2}

v_{i} =\sqrt{\frac{25^{2}*4 }{3} }

v_{i} =28.86\frac{ft}{s}

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4 years ago
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Your answer would be : A transmission electron microscope
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Answer:

a) increases

Explanation:

The increase in temperature causes the particles to move much faster. This in turn effects the collision rate of the particle which causes the chemical reaction. Thus the rate of chemical reaction increases.

So, we conclude that the rate of a chemical reaction is directly related to temperature. With increase in temperature there is an increase in the reaction rate and vice versa.  

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