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3 years ago

Help me solve this please

Physics

1 answer:

Wewaii [24]3 years ago

7 0

Answer:

<h2>option b , 2A</h2>

Explanation:

thus

so putting values we get,

I = 120/ R

for the value of R...

R(series) = R1 + R2 + R3

R= 20 + 20+ 20 = 60 ohm

thus, I=120/60 = 2

Therefore,

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How many nutrons are in an atom of copper

xeze [42]

Answer:

35 neutrons are in an atom of copper

8 0

3 years ago

Read 2 more answers

Given the Earth's density as 5.5 g/cm3 and the Moon's density as 3.34 g/cm3, determine the Roche limit for the Moon orbiting the

Assoli18 [71]

Answer:

The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth

Explanation:

The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.

The relation to determine Roche limit is:

$Roche\ limit=2.423\times R_{P}\times\sqrt[3]{\frac{D_{P} }{D_{M} } }$ ....(1)

Here $R_{P}$ is radius of planet and $D_{P}\ and\ D_{M}$ are density of planet and moon respectively.

According to the problem,

Density of Earth, $D_{P}$ = 5.5 g/cm³

Density of Moon, $D_{M}$ = 3.34 g/cm³

Consider $R_{E}$ be the radius of the Earth.

Substitute the suitable values in the equation (1).

$Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }$

$Roche\ limit= 2.86R_{P}$

8 0

3 years ago

A particle initially located at the origin has an acceleration of = 2.00ĵ m/s2 and an initial velocity of i = 8.00î m/s. Find (a

sergejj [24]

a. The particle has position vector

$\vec r(t)=\left(\left(8.00\dfrac{\rm m}{\rm s}\right)t\right)\,\vec\imath+\left(\dfrac12\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\right)\,\vec\jmath$

$\vec r(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)t\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath$

b. Its velocity vector is equal to the derivative of its position vector:

$\vec v(t)=\vec r'(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath$

c. At $t=7.00\,\mathrm s$ , the particle has position

$\vec r(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)(7.00\,\mathrm s)\,\vec\imath+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)^2\,\vec\jmath$

$\vec r(7.00\,\mathrm s)=\left(56.0\,\vec\imath+49.0\,\vec\jmath\right)\,\mathrm m$

That is, it's 56.0 m to the right and 49.0 m up relative to the origin, a total distance of $\|\vec r(7.00\,\mathrm s)\|=\sqrt{(56.0\,\mathrm m)^2+(49.0\,\mathrm m)^2}=74.4\,\mathrm m$ away from the origin in a direction of $\theta=\tan^{-1}\dfrac{49.0\,\mathrm m}{56.0\,\mathrm m}=41.2^\circ$ relative to the positive $x$ axis.

d. The speed of the particle at $t=7.00\,\mathrm s$ is the magnitude of the velocity at this time:

$\vec v(7.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\vec\imath+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)(7.00\,\mathrm s)\,\vec\jmath$

$\vec v(7.00\,\mathrm s)=\left(8.00\,\vec\imath+14.0\,\vec\jmath\right)\dfrac{\rm m}{\rm s}$

Then its speed at this time is

$\|\vec v(7.00\,\mathrm s)\|=\sqrt{\left(8.00\dfrac{\rm m}{\rm s}\right)^2+(14.0\dfrac{\rm m}{\rm s}\right)^2}=16.1\dfrac{\rm m}{\rm s}$

4 0

3 years ago

The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C

aniked [119]

The amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is is 8 times the initial amount of heat.

The temperature increment will lead to the increase in the internal energy of the object. This internal energy is the heat.

Given is the change in temperature ΔT = 7-4 =3°C., diameter D to 2D,

Q = Cp x ρ(4π/3)D³ x 3..................(1)

and Q' = Cp x ρ(4π/3)(2D)³ x 3

Q' = Cp x ρ(4π/3)8D³x 3..................(2)

Dividing both the equation, we have

Q' / Q =8

Q' = 8Q

Thus, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is 8 times the initial amount of heat.

Learn more about heat.

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#SPJ1

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2 years ago

As altitude increases in the troposphere and stratosphere, the air temperature does what?

natima [27]

Answer:

Explanation:

3 0

3 years ago

Help me solve this please​

Help me solve this please