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uranmaximum [27]
3 years ago
10

In a series circuit, if one bulb goes out the other blubs will stay lit. a. true b. false

Physics
2 answers:
Ganezh [65]3 years ago
5 0

Answer:

false

Explanation:

if one bulb goes out so does the other

andrey2020 [161]3 years ago
3 0
False, in a series circuit if one bulb goes out the other one will too because it breaks the circuit. Hope this helped !!

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A toy helicopter takes off and moves 6 m up and then 1 m back down. What
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the answer is 5 m up AKA "B"

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using a weston cadmium cell of 1.0283 v and a standard resistance of .1ohm a potentiometer was adjusted so that 1.0183 m was equ
anyanavicka [17]

Answer:

Explanation:

the value is -8 cm

3 0
2 years ago
This is data from a visible satellite image. What types of weather conditions are associated with the image?
babunello [35]
It look like a storm is forming out into the ocean and building pressure and maybe become a hurricane.
I hope this helps :)!!!
8 0
3 years ago
Read 2 more answers
A point on the end of a tuning fork moves in simple harmonic motion described by d = a sin ωt. Find ω given that the tuning fork
pantera1 [17]

Answer:

1609.1429 rad/sec

Explanation:

By using the relation Angular velocity and frequency as:

Angular velocity (ω) = 2×π×Frequency (ν)

Given the frequency = 256 vibrations per second.

So, Angular velocity can be calculated by using the above formula as:

Angular velocity (ω) = 2×π×Frequency (ν)

⇒Angular velocity (ω) = 2×π×256 rad/ sec

⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec

<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>

5 0
3 years ago
An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2
Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

M=-\frac{q}{p}

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

M=-\frac{200 cm}{50 cm}=-4.0

7 0
3 years ago
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