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dezoksy [38]
3 years ago
9

Which element's properties are similar to potassium?

Chemistry
2 answers:
12345 [234]3 years ago
6 0

Answer:

Potassium is an alkali metal

Explanation:

Symbol: K

Atomic number: 19

Atomic mass: 39.0983 u

Electron configuration: [Ar] 4s¹

Van der Waals radius: 280 pm

Electronegativity: 0.82

vekshin13 years ago
5 0

Answer:

Lithium, Sodium, Rubidium, Caesium, and Francium.

Explanation:

Like Potassium (K), those elements are alkali metals, found in Group 1 of the periodic table. Elements of a group share similar chemical properties with each other. So, any of those should work.

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Can someone please explain what orbits are? Like for example, how many orbits an element has
love history [14]

Answer: There are many possibilities for atomic orbits.

Explanation: In chemistry orbits, or orbitals, are the areas that electrons move around the nucleus of an atom. Think like the solar system.

There are three levels of orbitals (p,d, and f).

That should get you started. Use p, d and d described in your book to find out how many orbitals an atom has.

3 0
3 years ago
If 10.g of AgNo3 is available, what volume of 0.25 M AgNo3 can be prepared
Marianna [84]
The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.
3 0
4 years ago
A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
4 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
`I am holding a balloon containing 439 mL of gas over my fireplace. The temperature and pressure of the gas inside the balloon i
Andrew [12]

Answer:

- 0.07 °C

Explanation:

At constant pressure and number of moles, Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 439 mL  = 0.439 L ( 1 L = 0.001 mL )

V₂ = 0.378 L

T₁ = 317.15 K

T₂ = ?

Using above equation as:

\frac{0.439}{317.15}=\frac{0.378}{T_2}

T_2=\frac{0.378\cdot \:317.15}{0.439}=273.08\ K

The conversion of T(K) to T( °C) is shown below:

T( °C) = T(K) - 273.15  

So, <u>T = 273.08 - 273.15 °C = - 0.07 °C</u>

3 0
4 years ago
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