Answer: There are many possibilities for atomic orbits.
Explanation: In chemistry orbits, or orbitals, are the areas that electrons move around the nucleus of an atom. Think like the solar system.
There are three levels of orbitals (p,d, and f).
That should get you started. Use p, d and d described in your book to find out how many orbitals an atom has.
The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.
Answer:
The total energy change, ΔE, in kilojoules = -61.93 kJ
Explanation:
Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.
ΔE = ΔH - PΔV
Where,
ΔH = Change in enthalpy
ΔE = Change in internal energy
PΔV = Work done
Given that,
ΔH = -75.0 kJ = -75000 J
P = 43.0 atm
ΔV = Final volume - initial volume
= (2.00 - 5.00) = -3.00 L
PΔV = 43 × (-3.00) = -129 L atm
1 L atm = 101.325 J
-129 L atm = 129 × 101.325 = -13071 J
So ,
ΔE = ΔH - PΔV
= (-75000 J) - ( -13071 J)
= -75000 J + 13071 J
= -61929 J
Total energy change, ΔE = -61.929 kJ
Answer:
58.92 g EDTA
Explanation:
315.1 mL = .3151 L
M = Moles / Liter
.3151 L x <u>0.5 mol EDTA</u> x <u>374 g EDTA</u> = 58.92 g EDTA
1 L EDTA 1 mol EDTA
Answer:
- 0.07 °C
Explanation:
At constant pressure and number of moles, Using Charle's law
Given ,
V₁ = 439 mL = 0.439 L ( 1 L = 0.001 mL )
V₂ = 0.378 L
T₁ = 317.15 K
T₂ = ?
Using above equation as:
The conversion of T(K) to T( °C) is shown below:
T( °C) = T(K) - 273.15
So, <u>T = 273.08 - 273.15 °C = - 0.07 °C</u>
