A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854<span> kJ/°C. The temperature of the calorimeter increases from 23.44 to </span>30.57 °C<span>. </span>
Answer: sulfur pentafluoride
Explanation:
The rules for naming of binary molecular compound :
In the given formula, the lower group number element is written first in the name and keep its element name and the higher group number is written second.
First element i.e. sulphur in the formula is named first and keep its element name.
1) Gets a prefix if there is a subscript on it such as mono for 1, di for 2, tri for 3 and so on.
Second element i.e. fluorine is named second.
1) Use the root of the element name, if it is an anion then use suffix (-ide).
2) Always use a prefix on the second element such as mono for 1, di for 2, tri for 3 and so on.
Therefore, the chemical name of compound 
is sulfur pentafluoride
Well you’ll know it’s scientifically sound if enough definitive research and tests have been done AND show good results. Example:I could say that eating ants can cure cancer but if it’s not tested with good results it’s not scientifically sound
Given : Density of Bromine = 3.12 g/mL
Formula : Density = Mass / Volume
Part A :
Given Volume = 125 mL
Density = Mass / Volume
So, Mass = Density x Volume
= 3.12 x 125
= 390 grams
Part B :
Given mass = 85.0 gm
Density = Mass / Volume
So, Volume = Mass / Density
= 85 / 3.12
= 27.24 mL
Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
