Uracil (U) is not part of DNA but is part of RNA
Answer:
3- As cells get larger, the volume increases more than the surface area
Explanation:
As a cell develops, it grows larger and extends the cell membrane. Sadly, the volume rises greater than that of the surface area, and therefore the relative surface area usable to transfer resources to a unit cell volume declines gradually.
Answer:
D
Explanation:
The water molecules in the cell will want to move out of the cell into the pond in attempt to lower the salt concentration which will cause the cells to shrivel up with the loss of water. This is also called becoming hypertonic.
Answer:
A. Glucose:
As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.
B. lactose:
In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts. The same result will be in all test except in the case of a mutant repressor.
C. glucose and lactose:
In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose. the given two cases :
Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.
The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.
Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.
Answer:
when an object smashed into early Earth. .Explanation: no explanation just the answer
