Answer:
9ft
Step-by-step explanation:
The top of a ladder is placed against the side of a house. The ladder is 15ft long and the wall is 12ft high. How far from the wall will the base of the ladder be positioned if the top of the ladder meets the top of the wall.
We solve this question using Pythagoras Theorem
c² = a² + b²
Height of the wall = Opposite side = b = 12ft
Length of the ladder = Hypotenuse = c = 15ft
Distance between the wall and the base of the Ladder = Adjacent = a
Hence:
15² = a² + 12²
a² = 15² - 12²
a = √15² - 12²
a = √81
a = 9 ft
Therefore, the wall will be 9ft from the base of the ladder , if the top of the ladder meets the top of the wall
Note that the given cos(57°)cos(94°)-sin(57°)sin(94°) resembles the formula
cos a cos b - sin a sin b, which is cos (a+b).
Therefore, cos(57°)cos(94°)-sin(57°)sin(94° = cos (57+94) = cos 151.
x = 160
Steps:
x+20=180
Subtract 20 from both sides
x+20-20=180-20
20 is crossed out
180-20 = 160
x = 160
To check plug in 160 for x
160 + 20 = 180
180 = 180
Hope this helps you! (:
-Hamilton1757
For this you have to cross multiply.
so x is calories
3/50 = 6/x
6*50= 3x
300/3
x=100 calories
