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2 years ago

The length of a planet's orbit around a star is approximately 29,870,000 km.

Mathematics

1 answer:

Sliva [168]2 years ago

5 0

Answer:

745 k/hr

Step-by-step explanation:

mathematically, 1 day = 24 hours

1670 days = 1670 * 24 = 40,080 hours

The speed is thus;

(29,870,000)/40,080 = 745.259

= 745 km/h

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Brad is installing a hot tub in his 30 ft by 20 ft back yard. The hot tub has a radius of 5 feet. If he randomly shoots

ddd [48]

Answer:

13% chance

Step-by-step explanation:

Area of backyard = length * width

A = 30 ft * 20 ft

A = 600 $ft^{2}$

Area of bathtub = π $r^{2}$

A = π * $5^{2}$

A = 78.54 $ft^{2}$

Probability of arrow landing in tub can be found by dividing Area of the bathtub by the area of the backyard, and then multiplying by 100 for a percentage

Prob. = 78.54/600

Prob. = 0.13

Prob. = 0.13 * 100

Prob. = 13%

7 0

3 years ago

It was wartime when the Ricardos found out Mrs. Ricardo was pregnant. Ricky Ricardo was drafted and made out a? will, deciding t

ElenaW [278]

Answer:The girl will get $2,000, the mother $4,000 and the boy $8,000

Step-by-step explanation:

f the amount the girl gets = x

The mother gets twice as much as the girl = 2x

And the boy get twice as much as the mother = 4x

Overall

x + 2x + 4x = $14,000

7x = $14,000

Divide both sides by 7 so

x=$2,000

5 0

2 years ago

Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))

Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

$\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5$

Use properties:

$\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA$

Thus,

$\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11$