we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
where
a1 is the first term
d is the common difference between terms
n is the number of months (in this problem)
case a) Mandy
------> equation
in this equation the first month is April
case b) Bill
-------> equation
In this equation the first month is May
With the equation and the equation
calculate the attached table
therefore
the answer is
December
Answer:
0.5996 is the probability that none contain high levels of contamination.
Step-by-step explanation:
We are given the following information:
We treat lab specimen containing high levels of contamination as a success.
P( lab specimen containing high levels of contamination) = 0.12
Then the number of lab specimens follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 4
We have to find the probability that none of the lab specimen consist of high level of contamination.
We have to evaluate:
0.5996 is the probability that none contain high levels of contamination.
the complete question in the attached figure
Volume of the sand V=(1/3)*h*π*r²
we have that
h=30 mm
r=10 mm
v=(1/3)*30*π*10²=1000≈3140 mm³
the rate is 50 mm³/seg
50 mm³--------------------------------------> 1 seg
3140 mm³-------------------------------- X
x=3140/50=62.8 seg
the answer is 62.8 seg
