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stealth61 [152]
3 years ago
10

What is average velocity??​

Physics
2 answers:
valentina_108 [34]3 years ago
5 0

Answer:

The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another. Average velocity is a vector quantity.

andrew-mc [135]3 years ago
5 0
<h3>the arithematic mean of initial velocity and final velocity of a moving body is called average velocity</h3>

Explanation:

<h2><em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em></h2>
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While ice skating, Tabitha pushes against the wall to stretch her leg. What is the reaction force?
german
The force exterted and / or experienced by Tabitha's leg is an opposite reaction force equal to the amount of force she exerts when she pushes against the wall. This is explained further on Newton's third law of motion. Otherwise should the force she exerts on the wall overcomes the force of strength of the wall's resistance, the wall will break to the direction of tabitha's push.
4 0
3 years ago
Read 2 more answers
A battery-operated car uses a 12.0-V system. Find the charge the batteries must be able to move in order to accelerate the 956kg
DiKsa [7]
<h2>Answer:</h2>

1.99 x 10⁶C

<h2>Explanation:</h2>

The electrical energy (E_{E}) stored in the battery will give the car some kinetic energy (E_{K}) which will cause the car to move from rest to some other point.

i.e

E_{E} = E_{K}                 ------------------(i)

<em>But;</em>

E_{E} =  \frac{1}{2} x Q x V;            -------------------(ii)

Where;

Q = charge on the battery

V = potential difference or voltage of the battery = 12.0V

<em>Also</em>

E_{K} = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)            -----------------(iii)

Where;

m = mass of the car = 956kg

v = final velocity of the car = 158m/s

u = initial velocity of the car = 0   [since the car starts from rest]

<em>Substitute equations (ii) and (iii) into equation (i) as follows;</em>

\frac{1}{2} x Q x V = (\frac{1}{2} x m x v²) - (\frac{1}{2} x m x u²)       -----------------(iv)

<em>Substitute all necessary values into equation (iv) as follows;</em>

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (\frac{1}{2} x 956 x 0²)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²) - (0)

\frac{1}{2} x Q x 12.0 = (\frac{1}{2} x 956 x 158²)

\frac{1}{2} x Q x 12.0 = 11932792

6Q = 11932792

<em>Solve for Q;</em>

Q =  11932792 / 6

Q = 1988798.67 C

Q = 1.99 x 10⁶C

Therefore, the amount of charge the batteries must have is 1.99 x 10⁶C

8 0
4 years ago
A golf ball is dropped from rest from a height of 9.50 m. It hits the pavement, then bounces back up, rising just 9.70 m before
ipn [44]
The ball is in the air for 27.70m because
9.5+9.7=19.2...
9.7-1.2=8.5...
19.2+8.5=27.70...

5 0
4 years ago
What is 34 + (5) × (1.2465) written with the correct number of significant figures?
bonufazy [111]

Answer: 40

Explanation:

= 34 + 5 * 1.2465

= ‭40.2325‬

= 40

The number of significant figures in the answer should be the same as the number with the least number of significant figures that any of the digits in the equation have.

32 has 2 significant figures so the answer has to be 2 significant figures which is 40.

7 0
3 years ago
A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
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