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3 years ago

What is average velocity??

Physics

2 answers:

valentina_108 [34]3 years ago

5 0

Answer:

The average velocity of an object is its total displacement divided by the total time taken. In other words, it is the rate at which an object changes its position from one place to another. Average velocity is a vector quantity.

andrew-mc [135]3 years ago

5 0

<h3>the arithematic mean of initial velocity and final velocity of a moving body is called average velocity</h3>

Explanation:

<h2><em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em></h2>

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A scientist adds different amounts of salt to 5 bottles of water. She then

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3 years ago

While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the

Verdich [7]

The magnitude of the force is 18.6 N

Explanation:

The work done by a force on an object is given by

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

For the block in this problem, we have

$W=-17.8 J$ is the work done

d = 1.35 m is the displacement of the block

$\theta=135^{\circ}$ is the angle between the force and the displacement

Solving for F, we find the magnitude of the force:

$F=\frac{W}{d cos \theta}=\frac{-17.8}{(1.35)(cos 135)}=18.6 N$

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brainly.com/question/6763771

brainly.com/question/6443626

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4 years ago

According to the Droppler effect, what appears to happen when a light source moves further away from an observer? (20pts)

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3 years ago

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Please Help

Degger [83]

Explanation:

The initial kinetic energy $KE_0$ is

$KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2$

$\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}$

The final kinetic energy $KE$ is

$KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2$

$\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}$

The work done W on the car is

$W = \Delta{KE} = KE - KE_0$

$\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}$

The power expended P is

$P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}$

$\:\:\:\:\:= 10.7\:\text{kW}$

8 0

3 years ago

What is average velocity??​

What is average velocity??