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nata0808 [166]
3 years ago
13

How many complete revolutions are needed to draw the angle 725°?

Physics
2 answers:
uysha [10]3 years ago
8 0
C. A complete revolution is 360 degree. two revolution is 720.
fiasKO [112]3 years ago
4 0

Answer:

725\ degree=2\ revolution                

Explanation:

We know that 1 complete revolution is equal to 360 degrees. We need to find the number of complete revolution needed to draw the angle of 725 degrees.  

Since, 1 revolution = 360 degrees

or

1\ revolution=2\pi \ radian

1\ degree=\dfrac{1}{360}\ revolution

725\ degree=\dfrac{725}{360}\ revolution

725\ degree=2.01\ revolution

or

725\ degree=2\ revolution

So, to draw an angle of 725 degrees, there are 2 revolutions. Hence, this is the required solution.

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A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this
wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

r=r_o\times A^{\frac{1}{3}}

r_o=1.25 \times 10^{-15} m = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

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r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}

r=4.6656\times 10^{-15} m=4.6656 fm

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) F=k\times \frac{q_1q_2}{a^2}

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q_1,q_2 = charges kept at distance 'a' from each other

F = electrostatic force between charges

q_1=+1.602\times 10^{-19} C

q_2=+1.602\times 10^{-19} C

Force of repulsion between two protons on opposite sides of the diameter

a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m

F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}

F=2.6527 N

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0
3 years ago
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