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nata0808 [166]
3 years ago
13

How many complete revolutions are needed to draw the angle 725°?

Physics
2 answers:
uysha [10]3 years ago
8 0
C. A complete revolution is 360 degree. two revolution is 720.
fiasKO [112]3 years ago
4 0

Answer:

725\ degree=2\ revolution                

Explanation:

We know that 1 complete revolution is equal to 360 degrees. We need to find the number of complete revolution needed to draw the angle of 725 degrees.  

Since, 1 revolution = 360 degrees

or

1\ revolution=2\pi \ radian

1\ degree=\dfrac{1}{360}\ revolution

725\ degree=\dfrac{725}{360}\ revolution

725\ degree=2.01\ revolution

or

725\ degree=2\ revolution

So, to draw an angle of 725 degrees, there are 2 revolutions. Hence, this is the required solution.

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How do we solve questions C and D? I already did A and B and I am confused on how to continue
aleksandrvk [35]

(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.

(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.

<h3>Work done in moving the charge from C to A</h3>

W = Fd

W = Kq²/d

  • from 0 origin to C, d = √(5² + 5²) = 7.07 m
  • from 0 origin to A, d = 5 m

W(C to A) = W(0 to C) + W(0 to A)

W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A)  = 0.0586 \ Kq^2\\\\W(C \ to \ A)  = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A)  = 7.62 \times 10^{-3} \ J

<h3>Work done in moving the charge from D to B</h3>
  • from 0 origin to D, d = √(5² + 5²) = 7.07 m
  • from 0 origin to B, d = 5 m

W(D to B) = W(0 to D) + W(0 to B)

W(D to B) = 7.62 x 10⁻³ J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

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Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.

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