While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
1 answer:
The magnitude of the force is 18.6 N
Explanation:
The work done by a force on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the block in this problem, we have
is the work done
d = 1.35 m is the displacement of the block
is the angle between the force and the displacement
Solving for F, we find the magnitude of the force:
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Answer:
Force = 186 N
Explanation:
Torque is the rotational equivalent of linear force. It can be easely calculated using the formula :
Where is a vector that from the origin of the coordinate system to the point at which the force is applied (the position vector),
is the applied force.
The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench. By doing this we have that (the magnitud of the position vector) is 35cm.
Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :
Now using the torque formula:
Where is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector
, thus :
so the force is approximately 186 N.