While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the

Question

4 years ago

11

force?(unit=N) PLEASE HELP. I WILL MARK BRAINLIEST FOR THE RIGHT ANSWER

1 answer:

Verdich [7] · Answer 1 · 2021-11-08T14:16:20+03:00

The magnitude of the force is 18.6 N

Explanation:

The work done by a force on an object is given by

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

For the block in this problem, we have

$W=-17.8 J$ is the work done

d = 1.35 m is the displacement of the block

$\theta=135^{\circ}$ is the angle between the force and the displacement

Solving for F, we find the magnitude of the force:

$F=\frac{W}{d cos \theta}=\frac{-17.8}{(1.35)(cos 135)}=18.6 N$

Learn more about work here:

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