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3 years ago

What changes and challenges have you noticed in your relationship with your friends? Write a paragraph

Physics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

While in a relationship, friends can influence you to love your partner in different ways, sometimes because of how they also relate with their partners or what they say to you about your partner or the advice they give about and in your relationship.

Explanation:

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A toy gun uses a spring to project a 5.3 - g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the

Vikki [24]

Answer:

v = 1.16 m/s

Explanation:

As per work energy theorem we know that work done by all forces on the sphere is equal to the change in kinetic energy of the sphere

So here we will have

$\frac{1}{2}kx^2 - F_f .d = \frac{1}{2}mv^2$

here we know that

$F_f = 0.032 N$

k = 8 N/m

now we have

$\frac{1}{2}(8)(0.05^2) - (0.032)(0.15 + 0.05) = \frac{1}{2}(0.0053)v^2$

$0.01 - 6.4 \times 10^{-3} = 2.65 \times 10^{-3} v^2$

$v = 1.16 m/s$

7 0

4 years ago

When the velocity of the car is constant the force of friction is?

miv72 [106K]

..... equal to the force from the engine pushing the car forward.

That's why the car is not accelerating. The horizontal forces on it
are balanced.

6 0

3 years ago

Suppose a 65.5 kg gymnast climbs a rope. What is the tension in the rope if she climbs at a constant speed

natali 33 [55]

The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Given:

Mass of gymnast, m = 65.5 kg

The speed 'v' of gymnast is constant

Solution:

Consider the free-body diagram of the system as shown below.

Balancing forces along the vertical axis we get:

ΣFy = 0

Thus, we get:

F = ma - (1)

where, m is mass of gymnast

a is acceleration of gymnast (a = 0m/s², as the speed is constant)

Also,

F = T - mg -(2)

where, T is tension in the rope

g is acceleration due to gravity

Equating (1) & (2), we get:

ma = T - mg

Re-arranging the equation, we get:

T = m(a+g)

Applying values in above equation we get:

T = (65.5 kg)(0 m/s²+9.8 m/s²)

T = 641.9 N

Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Learn more about tension here:

<u>brainly.com/question/14294135</u>

#SPJ4

7 0

2 years ago

This type of reaction is most like breaking a rack of balls at the start of a game of pool:

Svet_ta [14]

The answer is b fission hope this helps

5 0

4 years ago

What is the terminal velocity of a 6.00-kg mass object in falling with a drag force with a magnitude that depends on speed, v, a

3241004551 [841]

When object reached the terminal speed then its acceleration is zero

So as per Newton's II law we can say

$F_{net} = 0$

now in that case we can say that net force is zero so here weight of the object is counter balanced by the drag force when it will reach at terminal speed

so we can write

$mg - F_d = 0$

so here we are given that

$F_d = 30$

$6*9.8 - 30*v = 0$

$58.8 - 30 *v = 0$

$v = \frac{58.8}{30}$

$v = 1.96 m/s$

so terminal speed will be nearly 2 m/s

6 0

3 years ago