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Mars2501 [29]
2 years ago
12

Hhheleppppp urgggeenttt

Mathematics
1 answer:
tekilochka [14]2 years ago
6 0
They intercept at (-1,5)
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Can someone help me :(
nikdorinn [45]

Answer:

A is the correct answer

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8 0
2 years ago
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Write 0.000739 in scientific notation.
jek_recluse [69]

Answer:

7.39 × 10-4^-4

Step-by-step explanation:

6 0
3 years ago
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Do you guys know 1.2n-1.5=0.45n
Lera25 [3.4K]

Answer:

n = 2

Step-by-step explanation:

1.2n - 1.5 = 0.45n

collect like terms

1.2n - 0.45n = 1.5

0.75n = 1.5

divide both side by 0.75

0.75n/0.75 = 1.5/0.75

n =2

4 0
2 years ago
The volume of a storage tank is 3,375 cubic meters. The storage tank is in the shape of a cube. What is the length of each side?
Eva8 [605]
2,275 should be the length of each side.


Basically what you do is cut the cubic meters in half and subtract.

Have a great day!
6 0
2 years ago
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and
Valentin [98]

So we have a set of integers,

X=\{15,20,25,25,27,28,30,34\}

And we need to compute some stats.

First the range,

The range of data set is difference between the maximum and the minimum of the data set.

So the minimum is 15 and maximum is 34 therefore the range is 34 - 15 = 19.

Second the interquartile range,

The interquartile range of data set is the difference of the first and third quartiles.

First quartile is the value separating the lower quarter and higher three - quarters of the set. The first quartile is computed by taking median of the lower half of the sorted set. This is 15, 20, 25, 25 and it's median is 22.5

Third quartile is therefore the median of 27, 28, 30, 34 which is 29.

Next up, variance.

The variance of set measures how much data is spread out. For data set x_1,\dots, x_n with an average a,

\mathsf{var}(X)=\Sigma_{i=1}^{n}\dfrac{(x_i-a)^2}{n-1}

So first compute the average value which is actually a mean,

a=\dfrac{1}{2}\Sigma_{i=1}^{n}a_i

The sum \Sigma_{i=1}^{n}a_i of numbers in set is 204.

Divide this by number of elements in the set (8).

a=\dfrac{204}{8}=25.5

Then compute the variance,

\mathsf{var}(X)=\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}\approx\boxed{34.57}

And finally standard deviation,

Since have computed variance the standard deviation is nothing too hard. It's defined as a square root of variance,

\mathsf{sde}(X)=\sqrt{\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}}=\sqrt{34.57}\approx\boxed{5.88}

Hope this helps.

r3t40

6 0
2 years ago
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