Answer:
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 50 - 1 = 49
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0096
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.1 - 1.1 = 4
The upper end of the interval is the sample mean added to M. So it is 5.1 + 1.1 = 6.2.
The 95% confidence interval for the true average number of homes that a person owns in his or her lifetime is (4,6.2).
The absolute value is always positive:
For example, the absolute value of -5: | - 5 | = 5 and also the absolute value of 5 : | 5 | = 5
P = - 1 1/4
The absolute value of point P.
| P | = | - 1 1/4 | = 1 1/4
X= 19/12 which is 1.58 in decimal form
Here’s an example on how to write one.
Answer:O0
Step-by-step explanation:
2*(v-2)-(-3-2*v)=0
STEP
1
:
Equation at the end of step 1
(0 - 2 • (v - 2)) - (-2v - 3) = 0
STEP
2
:
Equation at the end of step 2
7 = 0
STEP
3
:
Equations which are never true:
3.1 Solve : 7 = 0