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svp [43]
3 years ago
6

Statements apply to the expression 8^3 ?check all that apply

Mathematics
1 answer:
hram777 [196]3 years ago
6 0

Answer: So, 8%3 = 2

Step-by-step explanation:

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17 13/18 divided by 2 7/9
erik [133]

let's firstly convert the mixed fractions to improper fractions and then divide.

\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}

7 0
3 years ago
I need help with this pleaseee
Elodia [21]

Answer:

34, D

Step-by-step explanation:

Change 4 and 1/4 to an improper fraction

4 1/4 = 17/4

Now, you would divide 17/4 by 1/8...

17/4 divided by 1/8

Reciprocate the fraction 1/8 and change the division sign to multiplication to get...

17/4 multiplied by 8/1

= 136 / 4

Simplify

136 / 4

= 34

So, you can grow 34 plants.

Hope this helps!

7 0
2 years ago
Why does a y-intercept not count as a zero?
Genrish500 [490]

Answer:

It only counts as a zero when the y-intercept is (0,0).

Step-by-step explanation:

The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.

7 0
3 years ago
Jack and Jill had a lemonade stand. At the end of the day they had 75 buckles and quarters totaling $6.75. How many of each type
vekshin1

Answer:

eat stool hahahahahahaahahah

8 0
3 years ago
The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate
Schach [20]

Answer:

(a)0.16

(b)0.588

(c)[s_1$ s_2]=[0.75,$  0.25]

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix P^k.

(a)

P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)

P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}

If the system is initially running, the probability of the system being down in the next hour of operation is the (a_{12})th$ entry of the P^2$ matrix.

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, S=[s_1$  s_2]

[s_1$  s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$  s_2]

Using a calculator to raise matrix P to large numbers, we find that the value of P^k approaches [0.75 0.25]:

Furthermore,

[0.75$  0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$  0.25]

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

[s_1$ s_2]=[0.75$  0.25]

4 0
3 years ago
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