2 years ago

With a.b.c=1 and a+b+c=1 Prove that:

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

7 0

Answer:

HOPE IT HELPS PLZ MARK ME BRAINLIEST

Step-by-step explanation:

abc=1

⟹c=1/ab

1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a)

=1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a)

=b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab)

=1+b+ab/(1+b+ab)

You might be interested in

A business committee decided to increase the area of their square parking lot. They increased the width of the parking lot by 60

valina [46]

Kaks pluss kaks on neli miinus

4 0

3 years ago

We're do I find a rate of change

SVEN [57.7K]

You can find the rate of change by taking it's derivative.

6 0

2 years ago

Read 2 more answers

Solve for x & y. 30x−42y=−6 and 5x−7y=−1

vladimir1956 [14]

Um.. Both of those equations are the exact same. Divide both sides of the first equation by 6. You get:

$\frac{30x - 42y}{6} = \frac{-6}{6} \\ 5x - 7y = -1$

That is the exact same as the second equation. This system has an infinite number of solutions. 5x - 7y = -1 is a line, so basically every point on that line is a solution to the system.

For example, $x = 0$ and $y = \frac{1}{7}$ would work, but so would $x = 1$ and $y = \frac{6}{7}$