There are two ways to do this.
The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34
OR
you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34
Either way, the final answer is 34
Answer:
13 units
Step-by-step explanation:
Im doin this in class to so i got you
the equation would be d=(8-(-5))2-(-3-(-2))2
Next solve in the parenthesis 13 power of 2 +-1 power of 2
Then do the powers 169+1
d=170
Then you square 170 which is 13.03840481
That simplifies to 13
yayyyy
Is about 24,000 because if your finding the amount he's withdrawing is about 24,000
Answer:
A) Real Roots
B) Imaginary Roots
C) Equal Roots
D) Unequal Roots
E) Rational Roots
F) Irrational Roots
Step-by-step explanation:
The equation with one variable , in which the highest power of variable is two , is know as QUADRATIC EQUATION
ex - 3x² + 4x + 7 = 0
Every quadratic equation gives to values of unknown variables and these values is called roots of equation .
The quadratic equation have three roots :
A) Real Roots
B) Imaginary Roots
C) Equal Roots
D) Unequal Roots
E) Rational Roots
F) Irrational Roots
The nature of Roots depends entirely on the value of it Discriminant
If D = 0 , Roots are real and equal
If D
, roots are real and unequal
If D
,roots are imaginary
where D = b² - 4ac for any quadratic equation ax² + bx + c = 0
Answer