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3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!! :)

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

Hey there!

The answers are as follows:

7.)

m∠1 = 85

m∠2 = 95

m∠3 = 85

m∠4 = 85

8.)

m∠1 = 60

m∠2 = 120

m∠3 = 60

m∠4 = 120

9.)

they all equal 90

10.) No. Parallel lines do not cross each other, but these, if extended, would cross. You could use a protractor by measuring corresponding angles, and if they aren't equal, they aren't parallel.

Have a terrifcly amazing day!

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5.62 as a whole number in simplest form

Tju [1.3M]

Answer:

5.62*100=562. not sure

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3 years ago

Draw triangle XYZ with vertices X (-3, 2), Y (4, -2) and Z (-3, -2) on the coordinate plane. Then find the area of the triangle

dmitriy555 [2]

Answer:

14 square units

Step-by-step explanation:

If you graph the points your triangle's height will be 4, and base would be 7.

A = 1/2bh 4 x 7 = 28, 28 x 1/2 = 14.

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7 0

3 years ago

Read 2 more answers

What's the value of x and y?

krok68 [10]

Answer:

x = 45 and y = 90

Step-by-step explanation:

Let the third angle be z

z = 180 - 135 (Linear Pair)

z = 45

Since its an iscosceles triangle,

<z = <x (angles opposite to equal sides have equal angles)

<x = 45 degree

<z + <x + <y = 180

45 + 45+ <y = 180

90 + <y = 180

<y = 180 - 90

<y = 90

Therefore x = 45 and y = 90

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6 0

3 years ago

Read 2 more answers

Can someone please help me with this

Mama L [17]

Answer:

27.

Equation of 2 tangent lines at the given curve going through point P is:

y = -7x + 1

y = x + 1

28.

Part 1: 400 feet

Part 2: Velocity is +96 feet/second (or 96 feet/second UPWARD) & Speed is 96 feet per second

Part 3: acceleration at any time t is -32 feet/second squared

Part 4: t = 10 seconds

29.

Part 1: Average Rate of Change = -15

Part 2: The instantaneous rate of change at x = 2 is -8 & at x = 3 is -23

Step-by-step explanation:

27.

First of all, the equation of tangent line is given by:

$y-y_1=m(x-x_1)$

Where m is the slope, or the derivative of the function

Now,

If we take a point x, the corresponding y point would be $x^2-3x+5$ , so the point would be $(x,x^2-3x+5)$

Also, the derivative is:

$f(x)=x^2-3x+5\\f'(x)=2x-3$

Hence, we can equate the DERIVATIVE (slope) and the slope expression through the point given (0,1) and the point we found $(x,x^2-3x+5)$

The slope is $\frac{y_2-y_1}{x_2-x_1}$

So we have:

$\frac{x^2-3x+5-1}{x-0}\\=\frac{x^2-3x+4}{x}$

Now, we equate:

$2x-3=\frac{x^2-3x+4}{x}$

We need to solve this for x. Shown below:

$2x-3=\frac{x^2-3x+4}{x}\\x(2x-3)=x^2-3x+4\\2x^2-3x=x^2-3x+4\\x^2=4\\x=-2,2$

So, this is the x values of the point of tangency. We evaluate the derivative at these 2 points, respectively.

$f'(x)=2x-3\\f'(-2)=2(-2)-3=-7\\f'(2)=2(2)-3=1$

Now, we find 2 equations of tangent lines through the point (0,1) and with respective slopes of -7 and 1. Shown below:

$y-y_1=m(x-x_1)\\y-1=-7(x-0)\\y-1=-7x\\y=-7x+1$

and

$y-y_1=m(x-x_1)\\y-1=1(x-0)\\y-1=x\\y=x+1$

So equation of 2 tangent lines at the given curve going through point P is:

y = -7x + 1

y = x + 1

28.

Part 1:

The highest point is basically the maximum value of the position function. To get maximum, we differentiate and set it equal to 0. Let's do this:

$s(t)=160t-16t^2\\s'(t)=160-32t\\s'(t)=0\\160-32t=0\\32t=160\\t=\frac{160}{32}\\t=5$

So, at t = 5, it reaches max height. We plug in t = 5 into position equation to find max height:

$s(t)=160t-16t^2\\s(5)=160(5)-16(5^2)\\=400$

max height = 400 feet

Part 2:

Velocity is speed, but with direction.

We also know the position function differentiated, is the velocity function.

Let's first find time(s) when position is at 256 feet. So we set position function to 256 and find t:

$s(t)=160t-16t^2\\256=160t-16t^2\\16t^2-160t+256=0\\t^2-10t+16=0\\(t-2)(t-8)=0\\t=2,8$

At t = 2, the velocity is:

$s'(t)=v(t)=160-32t\\v(2)=160-32(2)\\v(2)=96$

It is going UPWARD at this point, so the velocity is +96 feet/second or 96 feet/second going UPWARD

The corresponding speed (without +, -, direction) is simply 96 feet/second

Part 3:

We know the acceleration is the differentiation of the velocity function. let's find it:

$v(t)=160-32t\\v'(t)=a(t)=-32$

hence, the acceleration at any time t is -32 feet/second squared

Part 4:

The rock hits the ground when the position is 0 (at ground). So we equate the position function, s(t), to 0 and find time when it hits the ground. Shown below:

$s(t)=160t-16t^2\\0=160t-16t^2\\16t^2-160t=0\\16t(t-10)=0\\t=0,10$

We disregard t = 0 because that's basically starting. So we take t = 10 seconds as our answer and we know rock hits the ground at t = 10 seconds.

29.

Part 1:

The average rate of change is basically the slope, which is

Slope = Change in y/ Change in x

The x values are given, from 2 to 3, and we need to find corresponding y values by plugging in the x values in the function. So,

When x = 2, $y=f(2)=-(2)^3 + 4(2) + 2=2$

When x = 3, $y=f(3)=-(3)^3 + 4(3) + 2=-13$

Hence,

Average Rate of Change = $\frac{-13-2}{3-2}=-15$

Part 2:

The instantaneous rate of change is got by differentiating the function and plugging the 2 points and finding the difference.

First, let's differentiate:

$f(x)=-x^3+4x+2\\f'(x)=-3x^2+4$

Now, find the derivative at 3,

$f'(x)=-3x^2+4\\f'(3)=-3(3)^2+4=-23$

finding derivative at 2,

$f'(x)=-3x^2+4\\f'(2)=-3(2)^2+4=-8$

The instantaneous rate of change at x = 2 is -8 & at x = 3 is -23

6 0

3 years ago

Days on the market are shown for the 36 most recent home sales in the city of Sonando Hills. 16546208818045851658823266716813621

Volgvan

Solution

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given data

$\begin{gathered} 165,46,20,88,180,45,85,165,8,8,23,26,67,168,136,21,143,8,84,22,106,131,16,152,171,64,33,116,151,117,99,61,159 \\ 73,51,136 \end{gathered}$

STEP 2: Find the mean

$\begin{gathered} mean=\frac{sum\text{ of data values}}{number\text{ of data values}} \\ sum\text{ of data values}=3144 \\ Number\text{ of data values}=36 \\ mean=\frac{3144}{36}=87.33333333\approx87.33 \end{gathered}$

mean is 87.33

STEP 3: Find the median

$undefined$

5 0

1 year ago