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vitfil [10]
3 years ago
9

Solve using the quadratic formula x²+3x=5show work to please!!​

Mathematics
1 answer:
nadezda [96]3 years ago
3 0

I used m a t h w a y-buh just write the equation and round the answer to whatever your teacher wants.

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Days/ cost to rent a truck 1/34 2/50 3/66 4/82 A/ C=16d B/ C= 16d + 18 C/ C= 16d + 16 D/ C=18d + 16
Mamont248 [21]
Use the given information as (x, y) points.
You have
(1, 34)
(2, 50)
(3, 66)
(4, 82)
The difference between renting for 1 day and 2 days is 50 - 34 = 16.
The difference between renting for 2 days and 3 days is 66 - 50 = 16
The difference between renting for 3 days and 4 days is 82 - 66 = 16
For each day you rent you pay $16.
Now look at renting for 1 day.
The rental for 1 day is $16, but for 1 day you pay $34.
$34 - $16 = $18
There is an extra $18 in the rental for every day. The $18 is fixed.
That means, to rent a truck, you must pay a fixed amount of $18 plus $16 per day.

total cost = daily cost + fixed cost
total cost =       16d    +      16
c = 16d + 18
3 0
3 years ago
Read 2 more answers
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
Write the equation in slope-intercept form then change it to standard form with integer coefficients.
SCORPION-xisa [38]

Answer:

1. Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

2. Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

3. Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

Step-by-step explanation:

Slope intercept form:   y = mx + b

where:

  • y = y-coordinate
  • m = slope
  • x = x-coordinate
  • b = y-intercept

Standard form:  Ax + By = C

\textsf{1.  as} \ m=2: \ \ y = 2x + b

   \textsf{at} \  (6, 8): \ \ 8 = 2(6) + b

   \implies b = -4

Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

\textsf{2.  as} \  \ m = \dfrac12: \ \ y = \dfrac12x + b

    \textsf{at} \  (4, 1): \ \ 1 = \dfrac12(4) + b

    \implies b = -1

Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

\textsf{3.  as} \  \ m = \dfrac45: \ \ y = \dfrac45x + b

   \textsf{at} \  (1,5): \ \ 5 = \dfrac45(1) + b

   \implies b = \dfrac{21}{5}

Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

7 0
3 years ago
Pentagon VWXYZ is shown on the coordinate grid. A student reflected pentagon VWXYZ across the x-axis to create pentagon V’W’X’Y’
pav-90 [236]

Reflecting across the x axis maintains the same x coordinate, but changes the sign of the y coordinate.

So, the transformation is

(x,y)\mapsto (x,-y)

7 0
3 years ago
35 people paid a total of $245 for admission to a local soccer game. What is the price of admission?
DIA [1.3K]

35 people paid a total of $245 for admission to a local soccer game. What is the price of admission?

Answer: We are given that 35 people paid total of $245 for admission.

Now we need to find the price of one admission. To find the price of one admission we need to divide the total amount paid by the number of people.

Therefore, the price of admission is:

\frac{245}{35}=\ 7


7 0
3 years ago
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