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3 years ago

Is every whole number a multiple of 1?

Mathematics

1 answer:

marissa [1.9K]3 years ago

6 0

Yes, it is. Even 0. 1x0=0

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A hotel Manager needed to seat 250 guests at a wedding party. Can he seat them in groups of 5 or 10?

svet-max [94.6K]

The manager can do both but if he does 10 he will have 25 groups but if he does 5 he will have 50 groups so the simple way is 10 so he will have 25 groups

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4 years ago

A birthday cake in the shape of a circle needs to be decorated with icing. If the diameter of the cake is 5 inches, how much ici

Dmitry [639]

<h2>19.63495408 inches²</h2>

Area of a circle = πr²

Diameter = 5

The radius is half the diameter.

Radius = 2.5

π × 2.5² = 19.63495408

6 0

3 years ago

Which number is 247, 039 ruonded to the nearest thousand?

djverab [1.8K]

247,039 rounded to the nearest thousand becomes

247,000

7 0

3 years ago

Read 2 more answers

Assume the number of typo errors on a single page of a book follows Poisson distribution with parameter 1=3. Calculate the proba

asambeis [7]

Answer:

(i). 0.03981

(ii).0.0048

Step-by-step explanation:

The probability density function of Poisson distribution is:

$P(X=x,\lambda)=\frac{e^{-\lambda}\lambda^x}{x!} \; \;\;\,\; x=0,1,2,...$

Consider <em>X</em> is a number of typos error on a single page of a book and <em>X</em> follows the Poisson distribution with $\lambda = \dfrac{1}{3}$

(i) Exactly two typos:

$\begin{aligned}P(X = 2,\frac{1}{3})&=\frac{e^{-\frac{1}{3}}\frac{1}{3}^{2}}{2!}\\&=\frac{e^{-\frac{1}{3}}}{18}\\&=0.03981\end{aligned}$

(ii) Two or more typos:

$\begin{aligned}P(X\geq2,\frac{1}{3})&=1-[P(X=0)+P(X=1)+P(X+2)]\\&=1-[0.7165+0.2388+0.03981]\\&=1-0.9952\\&=0.0048\end{aligned}$

7 0

4 years ago

I am lost on what to do

Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

4 years ago