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Elena-2011 [213]
3 years ago
7

Please help me do my homework I have been stuck on this for ages!!

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
10%. The thing is telling me to use twenty characters ignore this lol
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A marketing researcher wants to test the hypothesis that, within the population, there are differences in the importance attache
Ira Lisetskai [31]

Answer: Analysis of variance

Step-by-step explanation:

Analysis of variance is the statistical test that's used in analyzing the differences among means. The analysis of variance is used to determine if a statistically significant differences exust between the means of the independent groups.

Based on the question given, the null hypothesis will be that no difference in the importance that's attached to shopping by the consumers living in different regions in the United States.

6 0
2 years ago
Three equivalent ratio of 48:36
Andre45 [30]
Three equivalent ratios of 48:36 are 12:9 ,24:18 ,16:12.
5 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
in a survey, 250 adults and children were asked whether they know how to swim. the surgery data are shown in the relative freque
Nadusha1986 [10]

Answer: D

Step-by-step explanation:

7 0
2 years ago
The figure below shows circle with center O and two perpendicular diameters
dlinn [17]

Answer:

Triangles OAB,BOC,COD,DOA are isocele and right , are thus equals and have the same hypothenus . The quadrilater ABCD is a diamond (having 4 sides equals) and its diagonals perpendicular is thus a square.

Step-by-step explanation:

3 0
3 years ago
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